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mafiozo [28]
4 years ago
14

How many moles are in 2.04 × 1024 molecules of h2o?

Chemistry
1 answer:
EleoNora [17]4 years ago
5 0

Answer:

3.4moles

Explanation:

Given parameters:

Number of molecules = 2.04 x 10²⁴

Unknown: Number of moles

Solution

We use the concept of mole to solve this kind of problem.

A mole is the amount of substance that contains Avogadro's number of particle i.e 6.02 x 10²³ molecules

Solving

For elementary particles:

Number of moles = \frac{number of particles}{6.02 x 10^{23} }¹ molecules

Number of moles = \frac{2.04 x 10^{24} }{6.02 x ^{23} }

Number of moles of H₂O = 0.34 x 10¹ = 3.4moles

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If the mass of one or two spheres increases, how does it affect the gravity between the two spheres?
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3 years ago
A human zygote has 46 chromosomes. This number of chromosomes represents what in a human cell?
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3 years ago
A sample of helium gas has a pressure of 1.20 atm at 22.0 C. At what Celsius temperature will the helium reach a pressure of 2.0
Anarel [89]

Answer: 36.6°C

Explanation:

Given that,

initial pressure of helium (P1) = 1.20 atm

Initial temperature (T1) = 22.0°C

Final temperature (T2) = ?

Final pressure of helium (P2) = 2.00 atm

Since pressure and temperature are given while volume is constant, apply the formula for pressure's law

P1/T1= P2/T2

1.20 atm / 22.0°C = 2.00 atm / T2

Cross multiply

1.20 atm•T2= 2.00 atm•22°C

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8 0
4 years ago
Show the calculation of the mass of Ca3(PO4)2 needed to make 200 ml of a 0.128 M solution.
gavmur [86]

Answer:

We need 7.94 grams of Ca3(PO4)2

Explanation:

Step 1: Data given

Volume of Ca3(PO4)2 = 200 mL = 0.2 L

Molarity = 0.128 M

Molar mass of Ca3(PO4)2 = 310.18 g/mol

Step 2: Calculate moles of Ca3(PO4)2

Moles = molarity * volume

Moles Ca3(PO4)2  = 0.128 M * 0.2 L

Moles Ca3(PO4)2  = 0.0256 moles

Step 3: Calculate mass of Ca3(PO4)2

Mass Ca3(PO4)2  = moles Ca3(PO4)2  * molar massCa3(PO4)2

Mass Ca3(PO4)2  = 0.0256 moles * 310.18 g/mol

Mass Ca3(PO4)2  = 7.94 grams

We need 7.94 grams of Ca3(PO4)2

3 0
3 years ago
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