Explanation:
(a) Since, it is given that the blocks are identical so distribution of charge will be uniform on both the blocks.
Hence, final charge on block A will be calculated as follows.
Charge on block A = 
= 4.35 nC
Therefore, final charge on the block A is 4.35 nC.
(b) As it is given that the positive charge is coming on block A
. This means that movement of electrons will be from A to B.
Thus, we can conclude that while the blocks were in contact with each other then electrons will flow from A to B.
Answer:
A. 1.172 metres
B. 6.82 Ns
C. 4.796 m/s
Explanation:
The total initial momentum is gotten by multiplying the mass and initial velocity of the both bodies.
The 1.40 kg block is at rest so velocity is zero and has no momentum.
The bullet of mass 22 g = 0.022 kg with velocity of 310 m/s
Momentum = 310*0.022
Momentum = 6.82 Ns.
If the bullet gets embedded they will both have common velocity v
6.82 = (0.022+1.40)v
6.82 = 1.422v
V = 6.82/1.422
V = 4.796 m/s
How high the block will rise after the bullet is embedded is given by
H = (U²Sin²tita)/2g
Where tita is 90°
H = (4.796² * sin²(90))/(2*9.81)
H =( 23.001616*1)/19.62
H = 1.172 metres
That would be a conduction.
Kinetic energy is calculated by using formula:
Ek = 1/2*m*v^2
Now we replace values of mass and speed in this formula.
Ek = 1/2*10*3^2 = 45.0J
When you have a formula and all variable values are given in the text of question just replace variable values in equation and find the final value.
Answer:
figuer it out we are all on our ownExplanation:
