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Mumz [18]
3 years ago
12

Help Please

Physics
1 answer:
densk [106]3 years ago
3 0

Answer:

Energy=3.1times 10^-17 J

Rest mass: 6.2 kg

Speed: 47.5 m/s

Wavelength: 2.659 times 10^-6

Momentum: 67.3 kg(m/s)

Explanation:

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a coil has n turns enclosing an area of a. in a physics laboratory experiment, the coil is rotated during the time interval δt f
Mrac [35]
The correct answer for the question that is being presented above is this one:

Phi = BAsin(theta) 
<span>1. Phi(i) = BA </span>
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3. EMF = N(phi(i)-phi(f))/deltat

Here are the follow-up questions:

<span>1. What is the total magnitude Phi_initial of the magnetic flux through the coil before it is rotated? </span>
<span>2. What is the magnitude Phi_final of the total magnetic flux through the coil after it is rotated? </span>
<span>3. What is the magnitude of the average emf induced in the coil?</span>
8 0
3 years ago
A solenoid having N turns and carrying a current of 2.000 A has a length of 34 00 cm. If the magnitude of the magnetic field gen
umka21 [38]

Answer:

B) 1218

Explanation:

N = Total number of turns in the solenoid

L = length of the solenoid = 34.00 cm = 0.34 m

B = magnetic field at the center of the solenoid = 9 mT = 9 x 10⁻³ T

i = current carried by the solenoid = 2.000 A

Magnetic field at the center of the solenoid is given as

B = \frac{\mu _{o}N i}{L}

9\times 10^{-3} = \frac{(4\pi\times 10^{-7} )N (2)}{0.34}

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The answer would be B.

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