Responder: A.) 24.5m / s B.) 30.625m C.) 89.375m
Explicación:
Dado lo siguiente:
Altura desde la cual se cae el cuerpo = 120 m
Tiempo (t) = 2.5s
A.) La velocidad que toma:
El cuerpo cayó desde una altura;
velocidad inicial (u) = 0
Para calcular v:
V = u + en
Donde a = aceleración debido a la gravedad = 9.8m / s
v = 0 + (9.8) (2.5)
v = 24.5 m / s
B) Cuánto ha disminuido.
Usando la ecuación de movimiento:
S = ut + 0.5at ^ 2
Donde S = distancia
S = 0 × 2.5 + 0.5 (9.8) (2.5 ^ 2)
S = 0 + 0.5 (9.8) (6.25)
S = 30.625 m
Esta es la distancia recorrida después de 2.5 segundos Altura o distancia ha disminuido en 30.625 m
C.) ¿CUÁNTO FALTA? Por lo tanto, 120m - 30.625m = 89.375m
Answer:
Explanation:
Two charged particles will vary in energy as we alter the distance between them.
Answer:
it can occur in all waves because all wave have a frequency
Use Newton's second law and the free body diagram to determine the net force and acceleration of an object. In this unit, the forces acting on the object were always directed in one dimension.
The object may have been subjected to both horizontal and vertical forces but there was no single force directed both horizontally and vertically. Moreover, when free-body diagram analysis was performed, the net force was either horizontal or vertical, never both horizontal and vertical.
Times have changed and we are ready for situations involving two-dimensional forces. In this unit, we explore the effects of forces acting at an angle to the horizontal. This makes the force act in two dimensions, horizontal and vertical. In such situations, as always in situations involving one-dimensional network forces, Newton's second law applies.
Learn more about Newton's second law here:-brainly.com/question/25545050
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Answer:
Double the current
Explanation:
The energy delivered by the heater is related to the current by the following relation:
E= 
let R * t = k ( ∴ R and t both are constant)
so E= k 
Now let:
E2= k I₂^2
E2= 4E
⇒ k I₂^2= 4* k
Cancel same terms on both sides.
I₂^2= 4*
taking square-root on both sides.
√I₂^2 = √4* I^2
⇒I₂= 2I
If we double the current the energy delivered each minute be 4E.
