Answer
How do you think a winter day in San Francisco will be different from Kansas City
Explanation
How do you think a winter day in San Francisco will be different from Kansas City
How do you think a winter day in San Francisco will be different from Kansas City
Answer:
11.76Newtons
Explanation:
Workdone = Force * distance
Given
Workdone = 180joules
Distance = 15.3 metres
Required
Force
From the formula;
Force - Work/distance
Force = 180/15.3
Force = 11.76Newtons
Hence the required force is 11.76Newtons
Answer:
B.) A disturbance that carries energy
Explanation:
The complete statement that describes a wave would be :
A wave is a disturbance that carries energy from one place to another
Other listed options are incorrect because:
Incorrect : A.) A collision of particles ---------> Conduction
Incorrect : C.) A movement of fluids ----------> Convection
Incorrect : D.) A group of electrically charged molecules ----------> Radiation
[ Correct on Edgenuity ]
Hope this helps you have a better understanding ! :D
Have a wonderful day !
Answer:
Explanation:
Let the initial velocity of small block be v .
by applying conservation of momentum we can find velocity of common mass
25 v = 75 V , V is velocity of common mass after collision.
V = v / 3
For reaching the height we shall apply conservation of mechanical energy
1/2 m v² = mgh
1/2 x 75 x V² = 75 x g x 10
V² = 2g x 10
v² / 9 = 2 x 9.8 x 10
v² = 9 x 2 x 9.8 x 10
v = 42 m /s
small block must have velocity of 42 m /s .
Impulse by small block on large block
= change in momentum of large block
= 75 x V
= 75 x 42 / 3
= 1050 Ns.
Answer:

Explanation:
Given:
- Initial temperature of water,

- final temperature of water,

- energy spent in one hour of walk,

- volumetric capacity of stomach,

<em>Now, let </em><em>m </em><em>be the mass of water at zero degree Celsius to be drank to spend 450 kilo-calories of energy.</em>
We know:
.....................................(1)
where:
m = mass of water
Q = heat energy
temperature difference
= specific heat capacity of water
<u>Putting values in the eq. (1):</u>


Since water has a density of 1 kilogram per liter, therefore the volume of water will be:
