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serious [3.7K]
4 years ago
13

How can the match remain unlit in the middle of the flame of a brusen burner

Chemistry
2 answers:
chubhunter [2.5K]4 years ago
8 0

Answer:

By leaving the air valve almost close, so the flow of oxygen is as low as the combustion is not carried out properly, therefore, the flame will not rise beyond the middle of the ideally whole flame.

Explanation:

Hello,

On the attached picture, you will find a scheme showing the flame behavior of a bunsen burner in which it is seen that the middle of the flame matches with the hottest temperature due to the complete combustion of the fuel. It is possible for the match to remain unlit in the middle of the whole flame if the airflow is as low as the combustion is not carried out properly as shown below  the middle of the flame; it implies that the feed of oxygen is low so its valve remains almost closed.

Best regards.

Arisa [49]4 years ago
4 0
A match can remain unlit in the middle of the flame of a bunsen burner by not having the needed substance to ignite it. The match would not have a certain amount of oxygen reaching it at the middle of the flame since almost all of the oxygen is supplied in the production of flame of the bunsen burner. Oxygen is always needed for something to burn.
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A certain kind of light has a wavelength of 4.6 micrometers what is the frequency of this light and gigahertz? Use c= 2.998 × 10
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Answer:

6.52×10⁴ GHz

Explanation:

From the question given above, the following data were obtained:

Wavelength (λ) = 4.6 μm

Velocity of light (v) = 2.998×10⁸ m/s

Frequency (f) =?

Next we shall convert 4.6 μm to metre (m). This can be obtained as follow:

1 μm = 1×10¯⁶ m

Therefore,

4.6 μm = 4.6 μm × 1×10¯⁶ m / 1 μm

4.6 μm = 4.6×10¯⁶ m

Next, we shall determine frequency of the light. This can be obtained as follow:

Wavelength (λ) = 4.6×10¯⁶ m

Velocity of light (v) = 2.998×10⁸ m/s

Frequency (f) =?

v = λf

2.998×10⁸ = 4.6×10¯⁶ × f

Divide both side by 4.6×10¯⁶

f = 2.998×10⁸ / 4.6×10¯⁶

f = 6.52×10¹³ Hz

Finally, we shall convert 6.52×10¹³ Hz to gigahertz. This can be obtained as follow:

1 Hz = 1×10¯⁹ GHz

Therefore,

6.52×10¹³ Hz = 6.52×10¹³ Hz × 1×10¯⁹ GHz / 1Hz

6.52×10¹³ Hz = 6.52×10⁴ GHz

Thus, the frequency of the light is 6.52×10⁴ GHz

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