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bonufazy [111]
3 years ago
13

The eagle has landed was said when man landed on mars or on the moon

Chemistry
1 answer:
nekit [7.7K]3 years ago
7 0
The moon, man has not been to mars yet
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Which of the following is an example of a covalent bond?
loris [4]

Answer:

C. H2O

yep this one is right

4 0
2 years ago
A student needs to prepare 100. mL of 0.612 M Cu(NO3)2 solution. What mass, in grams, of copper(II) nitrate should the student u
Temka [501]

Answer: 11.5 grams

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution

Molarity=\frac{n\times 1000}{V_s}

where,

Morality = 0.612 M

n= moles of solute  

V_s = volume of solution in ml = 100 ml

Now put all the given values in the formula of molarity, we get

0.612=\frac{n\times 1000}{100ml}

n=0.0612moles

Mass={\text {moles of solute }}{\times {\text {molar mass}}=0.0612moles\times 187.56g/mol=11.5g

Therefore, the mass of copper (II)nitrate required is 11.5 grams

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3 years ago
Name two metalloids that are semiconductors
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Boron.

Silicon.

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Why are cells important?
victus00 [196]
They are the basic components of life or the basic building blocks of life
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How many moles of na2co3 are necessary to reach stoichiometric quantities with cacl2
lbvjy [14]

0.0102 moles Na₂CO₃ = 1.08g of Na₂CO₃ is necessary  to reach stoichiometric quantities with cacl2.

<h3>Explanation:</h3>

Based on the reaction

CaCl₂ + Na₂CO₃ → 2NaCl + CaCO₃

1 mole of CaCl₂ reacts per mole of Na₂CO₃

we have to calculate how many moles of CaCl2•2H2O are present in 1.50 g

  • We must calculate the moles of CaCl2•2H2O using its molar mass (147.0146g/mol) in order to answer this issue.
  • These moles, which are equal to moles of CaCl2 and moles of Na2CO3, are required to obtain stoichiometric amounts.
  • Then, we must use the molar mass of Na2CO3 (105.99g/mol) to determine the mass:

<h3>Moles CaCl₂.2H₂O:</h3>

1.50g * (1mol / 147.0146g) = 0.0102 moles CaCl₂.2H₂O = 0.0102moles CaCl₂

Moles Na₂CO₃:

0.0102 moles Na₂CO₃

Mass Na₂CO₃:

0.0102 moles * (105.99g / mol) = 1.08g of Na₂CO₃ are present

Therefore, we can conclude that 0.0102 moles Na₂CO₃  is necessary.to reach stoichiometric quantities with cacl2.

To learn more about stoichiometric quantities visit:

<h3>brainly.com/question/28174111</h3>

#SPJ4

7 0
2 years ago
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