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bonufazy [111]
3 years ago
13

The eagle has landed was said when man landed on mars or on the moon

Chemistry
1 answer:
nekit [7.7K]3 years ago
7 0
The moon, man has not been to mars yet
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Give the molecular geometry and number of electron groups for sf4. give the molecular geometry and number of electron groups for
Andrei [34K]

Answer:

5 electron groups, see saw

Explanation:

During the formation of SF4, the sulfur atom usually bonds with each of four fluorine atoms where 8 of valence electrons are used. The four fluorine atoms have 3 lone pairs of electrons in its octet which will further utilize 24 valence electrons. In addition, two electrons are present as a lone pair on the sulfur atom. We can determine sulfur’s hybridization state by counting of the number of regions of electron density on sulphur (the central atom in the molecule). When bonding takes place there is a formation of 4 single bonds to sulfur and it has 1 lone pair. Looking at this, we can say that the number of regions of electron density is 5. The hybridization state is sp3d.

SF4 molecular geometry is seesaw with one pair of valence electrons. The molecule is polar. The equatorial fluorine atoms have 102° bond angles instead of the actual 120° angle. The axial fluorine atom angle is 173° instead of the actual 180° bond angle.

3 0
3 years ago
How was the earth crust percentage determined ?
Troyanec [42]
By how thick or slim it is
5 0
3 years ago
What is a horizontal row of elements on a periodic table
Mariulka [41]

They are called Periods. Lesser known as series

3 0
2 years ago
Read 2 more answers
What is the abrviation of the element gold on the periodic table.
Natalka [10]

Au is the abbriviation


Hope this helps Buddy!


- Courtney

6 0
3 years ago
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A mixture of 117.9 g of P and 121.8 g of O, reacts completely to form P4O6 and P4O10. Find the masses of P4O6 and P4O10
Alex17521 [72]

Answer:

Mass of P4O6=103.4

            P4O10=133.48

Explanation:

Balanced reaction is:

8P +8O_{2}  ⇒P_{4} O_{6} +P_{4} O_{10}

Both reactant completely vanishes as equivalent of bot are equal.

Moles of P=\frac{117.9}{31} =3.80

Moles of O_{2} =\frac{117.9}{31} =3.80

No. of moles of formed product are equal and is \frac{1}{8}th of mole of any of reactant.

Thus weight of  P_{4} O_{6} =\frac{3.80}{8}×220 ≈103.41

        weight of  P_{4} O_{10} =\frac{3.80}{8}×284 ≈133.48

4 0
3 years ago
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