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3 years ago

Brainliest if answered in the next 5m

Chemistry

2 answers:

Nina [5.8K]3 years ago

5 0

The products are favored over the reactants

Ipatiy [6.2K]3 years ago

4 0

Products then Reactants. I hope i helped! :)

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g To what volume (in mL) should 5.07 mL of an 6.82 M acetic acid solution be diluted in order to obtain a final solution that is

denis-greek [22]

Answer:

The volume of the solution must be increased to 71.429 millimeters by adding 66.359 millimeters of solute to reduce molarity from 6.82 M to 0.49 M.

Explanation:

The molarity is a unit used for solution that is equivalent to the amount of moles of solute per unit volume of solution. That is:

$M = \frac{n_{st}}{V_{sol}}$

Where:

$n_{st}$ - Amount of moles of solute, measured in moles.

$V_{sol}$ - Volume of the solution, measured in liters.

To reduce the molarity of the solution, more millimeters of solvent should be added. Firstly, the amount of moles of acetic acid inside the 6.82 M solution needs to be determined ( $M_{o} = 6.82\,M$ and $V_{sol} = 5.07\times 10^{-3}\,L$ ):

$n_{st} = M_{o}\cdot V_{sol}$

$n_{st} = (6.82\,M)\cdot (5.07\times 10^{-3}\,L)$

$n_{st} = 0.035\,mol$

Now, the resulting volume of solution after diluting the acetic acid solution is: ( $M_{f} = 0.49\,M$ and $n_{st} = 0.035\,mol$ ):

$V_{sol} = \frac{n_{st}}{M_{f}}$

$V_{sol} = \frac{0.035\,mol}{0.49\,M}$

$V_{sol} = 71.429\times 10^{-3}\,L$

$V_{sol} = 71.429\,mL$ (1 L = 1000 mL)

The amount of solvent needed to dilute the solution is:

$\Delta V_{sol} = 71.429\times 10^{-3}\,L - 5.07\times 10^{-3}\,L$

$\Delta V_{sol} = 66.359 \times 10^{-3}\,L$

$\Delta V_{sol} = 66.359\,mL$ (1 L = 1000 mL)

The volume of the solution must be increased to 71.429 millimeters by adding 66.359 millimeters of solute to reduce molarity from 6.82 M to 0.49 M.

7 0

3 years ago

What is antifreeze used for?

pantera1 [17]

<span>An antifreeze is an additive which lowers the freezing point of a water-based liquid. An antifreeze mixture isused to achieve freezing-point depression for cold environments and also achieves boiling-point elevation to allow higher coolant temperature.</span>

5 0

3 years ago

Read 2 more answers

What is the total mass in grams of 0. 75 mole of so2.

Bas_tet [7]

Answer:

48.075g(or 48g in correct sig figs)***

Explanation:

$\frac{0.75mol}{1} *\frac{64.1g}{1 mol}$ =48.075g

*64.1g is the mass of SO2 which is calculated by simply taking the mass of sulfur and oxygen(but doubling it since there are two oxygens) and adding them together(32.1+2x16.0)

**btw the mol units cancel because of dimensional analysis in case anyone was wondering why

***if your teacher is like mine and specifically wants your answer in correct sig figs, use the answer in parentheses as the original problem only has 2 sig figs

7 0

2 years ago

11. You have 700 grams of AgO. How many moles are present?

solniwko [45]

<h2>Answer:</h2>

5.65moles

<h2>Explanations:</h2>

The formula for calculating the number of moles the compound contain is given as:

$moles=\frac{Mass}{Molar\text{ mass}}$

Given the following parameters

Mass of Ag = 700grams

Determine the molar mass of AgO

Molar mass = 107.87 + 16

Molar mass = 123.87g/mol

Determine the moles of AgO

$\begin{gathered} moles=\frac{700}{123.87} \\ moles\text{ of AgO}=5.65moles \end{gathered}$

Hence the moles of AgO present is 5.65moles

7 0

1 year ago

One group of students did an experiment to study the movement of ocean water. The steps of the experiment are listed below.

Mandarinka [93]

There was no equipment to create temperature difference in the water
hope this helps and can i get a brainly?
btw i make deals, if thi is wrong i own you ten questions you can ask me on my pf for free and i'll do it!

6 0

3 years ago

Read 2 more answers