The friction can be used as a stopper for the electricity so it can slow
or it can increace speed
Compound is formed when two or more chemical elements are chemically bonded together. elements are made of atoms
Answer:
pH = 3.49
Explanation:
We have a buffer system formed by a weak acid (HNO₂) and its conjugate base (NO₂⁻ coming from KNO₂). We can calculate the pH of a buffer ssytem using the Henderson-Hasselbach equation.
pH = pKa + log [base] / [acid]
pH = -log Ka + log [NO₂⁻] / [HNO₂]
pH = -log 4.50 × 10⁻⁴ + log 0.290 M / 0.210 M
pH = 3.49
<h3>
Answer:</h3>
Oxygen gas (O₂) is the rate limiting reactant and FeS₂ is the excess reactant.
<h3>
Explanation:</h3>
From the questions we are given;
4FeS₂(s) + 11O₂(g) → 2Fe₂O₃(s) + 8SO₂(s)
- Moles of FeS₂ are 26.62 moles
- Moles of Oxygen, O₂ are 59.44 moles
We are supposed to determine the limiting and excess reactants;
- From the equation of the reaction given; 4 moles of FeS₂ required 11 moles of Oxygen gas.
Working with the amount of reactants given;
- 26.62 moles of FeS₂ will require 73.205 moles of O₂ and only 59.44 moles of O₂ are available.
- On the other hand 59.44 moles of O₂ requires 21.615 moles of FeS₂, and we are given 26.62 moles of FeS₂ which means FeS₂ is in excess.
Conclusion;
We can conclude that Oxygen gas (O₂) is the rate limiting reactant and FeS₂ is the excess reactant.
The rate constant of the second order reaction is 0.137 M-1s-1.
<h3>What is the rate constant?</h3>
For the second order reaction we can write;
1/[A] = kt + 1/[A]o
[A]o = initial concentration
[A] = final concentration
k = rate constant
t = time
Now;
1/0.319 = 13.5k + 1/ 0.740
1/0.319 - 1/0.740 = 13.5k
3.13 - 1.35 = 13k
k = 3.13 - 1.35/13
k = 0.137 M-1s-1
Learn more about second order reaction:brainly.com/question/12446045
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