Answer:
CA ≈ 3.1 ft
Step-by-step explanation:
Using the tangent ratio in the right triangle
tan40° =
=
=
( multiply both sides by CA )
CA × tan40° = 2.6 ( divide both sides by tan40° )
CA =
≈ 3.1 ft ( to the nearest tenth )
<h3>
Answer: -3x-3y=-30= x=−y+10 </h3><h3>x+y+10= x=−y+10</h3>
Answer: 2,100 = 0.02(42) + b
2,100 = 50(42) + b
Step-by-step explanation: good day man
The slope-intercept form is
y=mx+b
, where m is the slope and b is the y-intercept.
y=mx+b
Find the values of
m
and
b
using the form
y
=
m
x
+
b
.
\m
=
2
b
=
−
3
The slope of the line is the value of
m
, and the y-intercept is the value of
b
.
Slope:
2
y-intercept:
(
0
,
−
3
)
Any line can be graphed using two points. Select two
x
values, and plug them into the equation to find the corresponding
y
values.
Tap for fewer steps...
Find the x-intercept.
Tap for more steps...
x-intercept(s):
(
3
2
,
0
)
Find the y-intercept.
Tap for more steps...
y-intercept(s):
(
0
,
−
3
)
Create a table of the
x
and
y
values.
x
y
0
−
3
3
2
0
m
=
2
b
=
−
3
The slope of the line is the value of
m
, and the y-intercept is the value of
b
.
Slope:
2
y-intercept:
(
0
,
−
3
)
Any line can be graphed using two points. Select two
x
values, and plug them into the equation to find the corresponding
y
values.
Tap for fewer steps...
Find the x-intercept.
Tap for more steps...
x-intercept(s):
(
3
2
,
0
)
Find the y-intercept.
Tap for more steps...
y-intercept(s):
(
0
,
−
3
)
Create a table of the
x
and
y
values.
x
y
0
−
3
3
2
0
I'm so sorry it layed out like this my computer is being st00pid
Answer:
11 am
Step-by-step explanation:
Bus A and Bus B leave the bus depot at 9 am.
Bus A takes 30 minutes to complete its route once
Bus B takes 40 minutes to complete its route once.
We solve this finding the Lowest Common Multiple of the minutes each bus uses to complete it's route
30 = 3 × 10
40 = 4 × 10
= 3 × 4 × 10
= 120 minutes
120 minutes after 9 am is
60 minutes = 1 hour
60 minutes = 1 hour
= 2 hours.
9am + 2 hours
= 11 am.
Therefore, they be back at the bus depot together at 11 am