t(f) = 27*f
g(t) = $0.04*27*f
without the value for f (the number of friends) that is the farthest this can be solved.
1*n-10 = (5/6)*n-((1/3)*n)-7 // - (5/6)*n-((1/3)*n)-7
1*n-((5/6)*n)+(1/3)*n-10+7 = 0
n+(-5/6)*n+(1/3)*n-10+7 = 0
1/2*n-3 = 0 // + 3
1/2*n = 3 // : 1/2
n = 3/1/2
n = 6
That's just in case you had to show your work lol^^
Answer:
B.(-5,-7)
Step-by-step explanation:
According to the rule of rotation if you were to have a 270* clockwise you would first switch the x and y values. Ex: (-7,5) -> (5,-7). next you would make the original y coordinate a negative. (5,-7) -> (-5,-7).
Answer:
Step-by-step explanation:
2.5 miles = 12 fishes
Therefore,
8 miles = 12*8/2.5=96/2.5= 960/25=38.4 fishes
