<u>Answer-</u>
<em>The probability that a randomly selected recipe does not contain sugar, given that it contains salt is 22.4%</em>
<u>Solution-</u>
The given table in the link shows the relative frequencies of recipes that contains sugar and salt, or contains at least one of those ingredients, or contains neither of those ingredients.
We have to find the conditional probability that the recipe doesn't contain sugar, given that it contains salt.
We know that, the conditional probability of occurrence of A given that B occurs is,
Putting these values,
Answer:
Yes
Step-by-step explanation:
If you add 87.84, 85, and 100 you get 272.84. Once you divide that by 3 you get 90.946, which would be your test average if you score 100 on your next test.
Answer:
Step-by-step explanation:
We want to simplify:
This is the same as:
Now let us convert the mixed numbers to improper fractions.
We multiply by the reciprocal of the second fraction to get:
Cancel out the common factors to obtain:
Answer:
1 and -0.6
Step-by-step explanation:
Answer:
i. x^2 – 1
ii. x^3 – 1
iii. x^4 - 1
Step-by-step explanation:
Products are obtained by multipliyng each left term by each rigth term as follows:
i. (x- 1)(x+ 1) = (x^2 – x + x - 1) = x^2 – 1 (equal terms with opposite sign substracts and the result is 0)
ii. (x- 1)(x^2 + x + 1) = (x^3 – x^2 + x^2 – x + x – 1) = x^3 – 1
iii. (x- 1)(x³ + x² + x + 1) = (x^4 – x^3 + x^3 – x^2 + x^2 – x + x – 1) = x^4 - 1
