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Evgen [1.6K]
3 years ago
10

Write a polynomial function of minimum degree with real coefficients whose zeros include those listed. Write the polynomial in s

tandard form.
7, -11, and 2 + 6i

f(x) = x4 - 53x2 + 468x - 3080

f(x) = x4 - 9x3 - 42x2 + 234x - 3080

f(x) = x4 - 117x2 + 468x - 3080

f(x) = x4 - 9x3 + 42x2 - 234x + 3080
Mathematics
1 answer:
r-ruslan [8.4K]3 years ago
6 0
The first thing you should do is to determine all the zeros, and you will have 7, -11, 2 + 6i, 2 - 6i.
 After that you have to <span>subtract and (x) from every each zero that you have above, which means 
</span>7-x, &#10;&#10; -11-x, &#10;&#10;2 + 6i-x,&#10;&#10; 2 - 6i-x&#10;
<span>And the last step is to multiply them together, and that's all you need! 
</span>(7-x)(-11-x)(2 + 6i-x)(2 - 6i-x)
<span>I am pretty sure that everything hase become clear! Regards.</span>
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Plz right answer=brainlyest
brilliants [131]

Answer:

B—283 cm^2

Step-by-step explanation:

SA=πr^2 + πrl

r=5

l=13

SA=π5^2 + π5*13

SA=π25 + π65

SA=78.5398 + 204.2035

SA=282.7433

SA=283=B

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3 years ago
2x−8=20 steps to solving
Art [367]
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Suppose the graph of a cubic polynomial function has the same zeroes and passes through the coordinate (0, –5).
Alexeev081 [22]
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