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Evgen [1.6K]
4 years ago
10

Write a polynomial function of minimum degree with real coefficients whose zeros include those listed. Write the polynomial in s

tandard form.
7, -11, and 2 + 6i

f(x) = x4 - 53x2 + 468x - 3080

f(x) = x4 - 9x3 - 42x2 + 234x - 3080

f(x) = x4 - 117x2 + 468x - 3080

f(x) = x4 - 9x3 + 42x2 - 234x + 3080
Mathematics
1 answer:
r-ruslan [8.4K]4 years ago
6 0
The first thing you should do is to determine all the zeros, and you will have 7, -11, 2 + 6i, 2 - 6i.
 After that you have to <span>subtract and (x) from every each zero that you have above, which means 
</span>7-x, &#10;&#10; -11-x, &#10;&#10;2 + 6i-x,&#10;&#10; 2 - 6i-x&#10;
<span>And the last step is to multiply them together, and that's all you need! 
</span>(7-x)(-11-x)(2 + 6i-x)(2 - 6i-x)
<span>I am pretty sure that everything hase become clear! Regards.</span>
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3 years ago
What is the equation that represents the line that passes through the point (2,6) and has a slope of -5?
tiny-mole [99]

Answer:

y = - 5x + 16

Step-by-step explanation:

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Here m = - 5, thus

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3 0
3 years ago
Solve using elimination<br><br> 2x+5y=34<br> x+2y=14
Darina [25.2K]

2x + 5y = 34

x+2y = 14


Multiply the second equation by two to create like terms for one variable.

2(x+2y = 14)

2x + 4y = 28


2x + 5y = 34

2x + 4y = 28 -- Subtract.


y = 34.28 = 6


Solve for x


x + 2(6) = 14

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Check:

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2 + 12 = 14

14 = 14


Answer:

X = 2

Y = 6

8 0
4 years ago
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