Choose the appropriate descriptor for the term square centimeter .

You want to make a ride so you do not want to exceed 1.1g’s, if the radius of the turns are 10m, then what is the maximum speed

Citrus2011 [14]

The maximum speed is 10.4 m/s

Explanation:

For a body in uniform circular motion, the centripetal acceleration is given by:

$a=\frac{v^2}{r}$

where

v is the linear speed

r is the radius of the circular path

In this problem, we have the following data:

- The maximum centripetal acceleration must be

$a=1.1 g$

where $g=9.8 m/s^2$ is the acceleration of gravity. Substituting,

$a=(1.1)(9.8)=10.8 m/s^2$

- The radius of the turn is

r = 10 m

Therefore, we can re-arrange the equation to solve for v, to find the maximum speed the ride can go at:

$v=\sqrt{ar}=\sqrt{(10.8)(10)}=10.4 m/s$

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8 0

4 years ago

If a machine increases force it must apply the force over a long distance? True or false

Eduardwww [97]

Answer: The machine must apply the force over a shorter distance. That's because a machine doesn't change the amount of work and work equals force times distance. Therefore, if force increases, distance must decrease

FALSE

HOPE THIS HELPS

4 0

3 years ago

A flywheel turns through 26 rev as it slows from an angular speed of 2.9 rad/s to a stop. (a) Assuming a constant angular accele

Misha Larkins [42]

a) The wheel takes 112.7 s to comes to rest

b) The angular acceleration of the wheel is $-0.0257 rad/s^2$

c) The wheel takes 33.0 s to complete 13 revolutions

Explanation:

a)

The rotational motion of the wheel is at constant angular acceleration, so we can use the equivalent of the suvat equations for rotational motion. In particular, to find the time the wheel takes to come to a stop, we use the following:

$\theta = (\frac{\omega_f+\omega_i}{2})t$

where:

$\theta$ is the angular displacement

$\omega_i$ is the initial angular speed

$\omega_f$ is the final angular speed

t is the time

For the wheel in this problem:

$\omega_i = 2.9 rad/s$

$\omega_f = 0$

$\theta = 26 rev \cdot (2\pi)= 163.4 rad$

And solving for t, we find the time:

$t=\frac{2\theta}{\omega_i + \omega_f}=\frac{2(163.4)}{0+2.9}=112.7 s$

b)

We can find the angular acceleration by using the equation:

$\alpha = \frac{\omega_f - \omega_i}{t}$

where here we have:

$\omega_f = 0$ is the final angular speed

$\omega_i = 2.9 rad/s$ is the initial angular speed

t = 112.7 s is the time

And substituting,

$\alpha = \frac{0-2.9}{112.7}=-0.0257 rad/s^2$

And the negative sign is because the wheel is decelerating.

c)

In order to find the time taken to complete 13 revolutions, we use the following suvat equation:

$\theta=\omega_i t+ \frac{1}{2}\alpha t^2$

where:

$\omega_i = 2.9 rad/s$ is the initial angular speed

$\theta = 13 rev \cdot (2\pi)=81.7 rad$ is the angular displacement

$\alpha=-0.0257 rad/s^2$ is the angular acceleration

Substituting into the equation:

$81.7 = 2.9 t +\frac{1}{2}(-0.0257)t^2\\0.0129t^2-2.9t+81.7 = 0$

which has two solutions:

t = 33.0 s

t = 191.8 s

And here we have to take the first solution (33.0 s), because it corresponds to the first time at which the angular displacement of the wheel is equal to 13 revolutions (the second solution is the time at which the angular displacement of the wheel returns to 13 revolutions, after the wheel has came to rest and it started to rotate in the opposite direction).

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5 0

4 years ago

Is it possible for two pieces of the same metal to have different recrystallization temperatures? Is it possible for recrystalli

Butoxors [25]

Answer:

Explained

Explanation:

Two pieces of the same metal can have different recrystallization temperatures if the pieces have been cold worked to different amounts. The piece of work cold worked to greater extend will have more internal energy to drive the recrystalline process and lower recrystallization temperature.

Yes, its possible that recrystallization to take place in some regions of a part before it does in other regions of the same part if the work has been unevenly strained or if the part have different thickness at different sections.

6 0

3 years ago

100 points please help

Eduardwww [97]

Answer:

The first picture is B The second picture electric current is the 1st one Voltage is the last one so that leaves resistance the middle picture. The last picture is A

Explanation:

7 0

2 years ago

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