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Airida [17]
3 years ago
5

What is the equation in slope-intercept form of the line that passes through the point (3,0) and is

Mathematics
1 answer:
Pie3 years ago
6 0

Answer:

The answer is B y = 1.5x – 4.5

Step-by-step explanation:

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Kazeer [188]

please recheck question i was trying to do with Pythagoras theorem and it came in decimal so please recheck the question

7 0
2 years ago
Help me please I need it
jenyasd209 [6]

Step-by-step explanation:

see the photo for explanation

5 0
3 years ago
Read 2 more answers
The problem is how many people must attend the third show so that the average attendance for three shows is 3000? And the other
Akimi4 [234]
An average is just the total attendance numbers / the number of performances.

Let's let the number of people in the third show be equal to x so we can write this as a formula, it's easier to read. x is just "some number we don't know"

The average is

Average=Total attendance/3
So
3000=(2580+2920+x)/3

So let's multiply by that 3 on both sides, make x easier to find

Average*3=2580+2920+x ( * means multiplied)

The average is 3000

So

2580+2920+x=3000*3
2580+2920+x=9000
 

Then we subtract those other attendances to get x on its own.

x=9000-2580-2920
x=3500





8 0
3 years ago
Read 2 more answers
For a square with a side length x + 1 , what is the area if x=9
Svetach [21]

Answer:

100 units squared

Step-by-step explanation:

The area of a square is A=s^2, where s is the side length. So, in your problem, the area would be A=(x+1)^2. If x = 9, then the formula would be A = (9+1)^2 = 100.

6 0
3 years ago
Read 2 more answers
A group of students are planning a mural at a wall the rectangular wall has dimensions of (6x+7) by (8x+5) and they are planning
zvonat [6]

Answer: 46x^2+73x+15

Step-by-step explanation:

The area of a rectangle can be calculated with the formula:

A=lw

l: the length of the rectangle.

w: the width of the rectangle.

The area of the remaning wall after the mural has been painted, will be the difference of the area of the wall and the area of the mural.

Knowing that the dimensions of the wall are (6x+7) by (8x+5), its area is:

A_w=(6x+7)(8x+5)\\\\A_w=48x^2+30x+56x+35\\\\A_w=48x^2+86x+35

As they are planning that the dimensions of the mural be (x+4) by (2x+5), its area is:

A_m=(x+4)(2x+5)\\\\A_m=2x^2+5x+8x+20\\\\A_m=2x^2+13x+20

Then the area of the remaining wall after the mural has been painted is:

A_{(remaining)}=A_w-A_m\\\\A_{(remaining)}=48x^2+86x+35-(2x^2+13x+20)\\\\A_{(remaining)}=48x^2+86x+35-2x^2-13x-20\\\\A_{(remaining)}=46x^2+73x+15

8 0
3 years ago
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