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snow_lady [41]
3 years ago
5

Given the Arithmetic sequence A1,A2,A3,A4 53, 62, 71, 80 What is the value of A38?

Mathematics
2 answers:
Tanya [424]3 years ago
4 0

Answer:

A_{38}=386

Step-by-step explanation:

We have been given an arithmetic sequence gas A_1,A_2,A_3,A_4 as :53,62,71,80. We are asked to find A _{38}.

We know that an arithmetic sequence is in format a_n=a_1+(n-1)d, where,

a_n = nth term,

a_1 = 1st term of sequence,

n = Number of terms,

d = Common difference.

We have been given that 1st term of our given sequence is 53.

Now, we will find d by subtracting 71 from 80 as:

d=80-71=9

A_{38}=53+(38-1)9

A_{38}=53+(37)9

A_{38}=53+333

A_{38}=386

Therefore, A_{38}=386.

Murrr4er [49]3 years ago
3 0

Answer:

A_{38}  = 350

Step-by-step explanation:

The 5th term of the arithmetic sequence is 53. We can write the equation:

a + 4d = 53...(1)

The 6th term of the arithmetic sequence is 62. We can write the equation:

a + 5d = 62...(2)

Subtract the first equation from the second one to get:

5d - 4d = 62 - 53

d = 9

The first term is

a + 4(9) = 53

a + 36 = 53

a = 53 - 36

a = 17

The 38th term of the sequence is given by:

A_{38} = a + 37d

A_{38}  = 17+ 37(9)

A_{38}  = 350

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