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2 years ago

Calculate the molarity of a solution with 233.772g sodium chloride dissolved in 2,000mL of water

Chemistry

1 answer:

LekaFEV [45]2 years ago

3 0

Answer:

The molarity is 2M

Explanation:

First , we calculate the weight of 1 mol of NaCl:

Weight 1mol NaCl= Weight Na + Weight Cl= 23 g+ 35, 5 g= 58, 5 g/mol

58,5 g---1 mol NaCl

233,772 g--------x= (233,772 g x1 mol NaCl)/58,5 g= 4 mol NaCl

A solution molar--> moles of solute in 1 L of solution:

2 L-----4 mol NaCl

1L----x0( 1L x4mol NaCl)/4L =2moles NaCl---> 2 M

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kirza4 [7]

Taking into account the definition of density, the density of the sample is 0.5 $\frac{g}{mL}$ .

It is necessary yo know that density is defined as the property that matter, whether solid, liquid or gas, has to compress into a given space.

In other words, density allows you to measure the amount of mass in a certain volume of a substance.

Then, the expression for the calculation of density is the quotient between the mass of a body and the volume it occupies:

$density=\frac{mass}{volume}$

In this case, you know:

mass= 6 g
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Then, replacing in the definition of density:

$density=\frac{6 g}{12 mL}$

Solving:

density= 0.5 $\frac{g}{mL}$

Finally, the density of the sample is 0.5 $\frac{g}{mL}$ .

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