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Andre45 [30]
3 years ago
13

Besides glycerol what 3 other molecules make up a triglyceride?

Chemistry
1 answer:
ICE Princess25 [194]3 years ago
6 0
Triglyceride is a molecule constituted by one one molecule of glycerol and 3 molecules of fatty acids. The structure of a glycerol is like a letter "E", where the vertical line ( | ) is the glycerol and the three horizontal lines are long chains of organic acids, each with one COOH group, called fatty acids.<span> The answer is that the other 3 molecules that make up a triglyceride are fatty acids.</span>
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Which term describes a chemical equation in which all highly soluble compounds are written as dissociated ions
BartSMP [9]

Answer: IONIC EQUATION.

Explanation:

A chemical equation is defined as the form by which a chemical reaction is represented mathematically. These are written in the form of symbols and chemical formulas of reactants and products which are taking part in the chemical reaction. A chemical equation can be written in two forms, these include:

--> MOLECULAR EQUATION: in this type of equations, the compounds are written and represented in a molecular form. This is sometimes referred to as a balanced equation.

--> IONIC EQUATION: This is a type of chemical equation in which the electrolytes in aqueous solution are expressed as dissociated ions. A typical illustrated example is seen in the reaction between AgNO3(aq) and NaCl(aq) :

Ag+(aq) + NO3-(aq) + Na+(aq) + Cl-(aq) → AgCl(s) + Na+(aq) + NO3-(aq)

The (aq) written in the above equation signifies they are in aqueous solution.

4 0
2 years ago
the elements helium (he), neon (ne), and xenon (xe) are all part of the same on the periodic table plz answer correctly gets a b
bagirrra123 [75]
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3 0
3 years ago
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The freezing point of benzene is 5.5°C. What is the freezing point of a solution of 2.60 g of naphthalene (C10H8) in 675 g of be
Mrac [35]

<u>Answer:</u> The freezing point of solution is 5.35°C

<u>Explanation:</u>

The equation used to calculate depression in freezing point follows:

\Delta T_f=\text{Freezing point of pure solution}-\text{Freezing point of solution}

To calculate the depression in freezing point, we use the equation:

\Delta T_f=iK_fm

Or,

\text{Freezing point of pure solution}-\text{Freezing point of solution}=i\times K_f\times \frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}

where,

Freezing point of pure solution = 5.5°C

i = Vant hoff factor = 1 (For non-electrolytes)

K_f = molal freezing point elevation constant = 4.90°C/m

m_{solute} = Given mass of solute (naphthalene) = 2.60 g

M_{solute} = Molar mass of solute (naphthalene) = 128.2 g/mol

W_{solvent} = Mass of solvent (benzene) = 675 g

Putting values in above equation, we get:

5.5-\text{Freezing point of solution}=1\times 4.90^oC/m\times \frac{2.60\times 1000}{128.2g/mol\times 675}\\\\\text{Freezing point of solution}=5.35^oC

Hence, the freezing point of solution is 5.35°C

3 0
3 years ago
Do you think placing an Alka-Seltzer in water causes a chemical reaction? <br>Explain Why.
VashaNatasha [74]
Well, yeah, because the chemicals in the AlkaSeltzer when in water, fizes, because of the chemicals in the pallet.
7 0
3 years ago
Look at the diagram below.
Irina-Kira [14]

Answer:

if charge of ion is positive then it will loose electron

if charge of ion is negative it will gain electron

4 0
3 years ago
Read 2 more answers
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