Answer:
14.3 g SO₃
Explanation:
2S + 3O₂ → 2SO₃
First, find the limiting reactant. To do that, calculate the mass of oxygen needed to react with all the sulfur.
5.71 g S × (1 mol S / 32 g S) = 0.178 mol S
0.178 mol S × (3 mol O₂ / 2 mol S) = 0.268 mol O₂
0.268 mol O₂ × (32 g O₂ / mol O₂) = 8.57 g O₂
There are 10.0 g of O₂, so there's enough oxygen. The limiting reactant is therefore sulfur.
Use the mass of sulfur to calculate the mass of sulfur trioxide.
5.71 g S × (1 mol S / 32 g S) = 0.178 mol S
0.178 mol S × (2 mol SO₃ / 2 mol S) = 0.178 mol SO₃
0.178 mol SO₃ × (80 g SO₃ / mol SO₃) = 14.3 g SO₃
Answer:
0.2g
Explanation:
All radiodecay follows the 1st order decay equation
A = A₀e^-kt
A => Activity at time (t)
A₀ => Initial Activity at time = 0
k => decay constant for isotope
T => time in units that match the decay constant
Half-Life Equation => kt(½) = 0.693 => k = 0.693/34 min = 0.0204min¹
A = A₀e^-kt = (26g)e^-(0.0204/min)(238min) = (26g)(0.0078) = 0.203g ~ 0.2g (1 sig fig).
The concentration of solids is constant and usually taken equal to unity ,therefore it does not appear in the equilibrium constant ,so adding or removing solid has no effect. So According to Le Chatelet's Principle the amount of solid reactant or product present does not have an impact on the equilibrium
What is Le Chatelet's Principle ?
The position of the equilibrium in a chemical reaction can be predicted with the aid of Le Chatelet's Principle in response to changes in temperature, concentration, or pressure. This is crucial, especially for industrial applications where it's crucial to predict and maximize yields.
According to Le Châtelet's principle, if a dynamic equilibrium is upset by changing the conditions, the equilibrium position will move to compensate for the change and restore the equilibrium.
To know about Le Chatelet's Principle from the link
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He ^ 2+
Helium has two electrons the 2+ means that it has lost its two electrons leaving it with none.
