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Anika [276]
3 years ago
10

Which component of a plant makes the cell walls around plant cells tough and allows branches, stems, and leaves to be strong

Chemistry
1 answer:
Vsevolod [243]3 years ago
8 0
<h3><u>Answer;</u></h3>

Cellulose

<h3><u>Explanation</u>;</h3>
  • Cellulose is a polysaccharide and the most abundant organic compound on the Earth's surface.
  • <em><u>It  is an important organic molecule due to its strong structure which provides a wide variety of functions. </u></em>
  • <em><u>Cellulose is a major component of tough cell walls that surround plant cells and is what makes plant stems, leaves, and branches very  strong.</u></em>
  • The molecules of cellulose are arranged such that they are parallel to each other joined by hydrogen bond. this arrangement forms long structures that combine with other cellulose molecules producing a strong support structure.
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In the reaction below, if 5.71 g of sulfur is reacted with 10.0 g of oxygen, how many grams of sulfur trioxide will be produced?
yawa3891 [41]

Answer:

14.3 g SO₃

Explanation:

2S + 3O₂ → 2SO₃

First, find the limiting reactant.  To do that, calculate the mass of oxygen needed to react with all the sulfur.

5.71 g S × (1 mol S / 32 g S) = 0.178 mol S

0.178 mol S × (3 mol O₂ / 2 mol S) = 0.268 mol O₂

0.268 mol O₂ × (32 g O₂ / mol O₂) = 8.57 g O₂

There are 10.0 g of O₂, so there's enough oxygen.  The limiting reactant is therefore sulfur.

Use the mass of sulfur to calculate the mass of sulfur trioxide.

5.71 g S × (1 mol S / 32 g S) = 0.178 mol S

0.178 mol S × (2 mol SO₃ / 2 mol S) = 0.178 mol SO₃

0.178 mol SO₃ × (80 g SO₃ / mol SO₃) = 14.3 g SO₃

3 0
3 years ago
Which type of silk is the strongest? (1 po o nonbiodegradable
vesna_86 [32]

Answer:

d. major ampullate

6 0
2 years ago
Current Question:
IRISSAK [1]

Answer:

0.2g

Explanation:

All radiodecay follows the 1st order decay equation

A = A₀e^-kt

A => Activity at time (t)

A₀ => Initial Activity at time = 0

k => decay constant for isotope

T => time in units that match the decay constant

Half-Life Equation => kt(½) = 0.693 => k = 0.693/34 min = 0.0204min¹

A = A₀e^-kt  = (26g)e^-(0.0204/min)(238min) = (26g)(0.0078) = 0.203g ~ 0.2g (1 sig fig).

7 0
3 years ago
According to le châtelier’s principle, the amount of solid reactant or product present does not have an impact on the equilibriu
Inessa05 [86]

The concentration of solids is constant and usually taken equal to unity ,therefore it does not appear in the equilibrium constant ,so adding or removing solid has no effect. So According to Le Chatelet's Principle the amount of solid reactant or product present does not have an impact on the equilibrium

What is  Le Chatelet's Principle ?

The position of the equilibrium in a chemical reaction can be predicted with the aid of Le Chatelet's Principle in response to changes in temperature, concentration, or pressure. This is crucial, especially for industrial applications where it's crucial to predict and maximize yields.

According to Le Châtelet's principle, if a dynamic equilibrium is upset by changing the conditions, the equilibrium position will move to compensate for the change and restore the equilibrium.

To know about Le Chatelet's Principle from the link

brainly.com/question/2943338

#SPJ4

5 0
1 year ago
What’s the correct answer
butalik [34]
He ^ 2+

Helium has two electrons the 2+ means that it has lost its two electrons leaving it with none.
3 0
3 years ago
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