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Ad libitum [116K]
2 years ago
9

As an athlete exercises, sweat is produced and evaporated to help maintain a proper body temperature. On average, an athlete los

es approximately 307 g of sweat during an hour of exercise. How much energy is needed to evaporate the sweat that is produced? The heat of vaporization for water is 2257J/g. energy required:
Chemistry
1 answer:
dmitriy555 [2]2 years ago
7 0

<u>Answer:</u> For the given amount of sweat lost, the amount of energy required will be 692,899 Joules.

<u>Explanation:</u>

We are given:

Heat of vaporization for water = 2257 J/g

Amount of sweat lost = 307 grams

Applying unitary method:

For 1 g of sweat lost, the energy required is 2257 Joules

So, for 307 grams of sweat lost, the energy required will be = \frac{2257J}{1g}\times 307g=692,899J

Hence, for the given amount of sweat lost, the amount of energy required will be 692,899 Joules.

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Answer:

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Explanation:

(a) considering the data given

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Vapour pressure P2 = 273.15 at Temperature T2= 315.58 K)

Using the Clausius-Clapeyron Equation

ln (P2/P1) = (ΔH/R)(1/T2 - 1/T1)

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(b) using the Equation ΔG°=ΔH° - TΔS to solve forΔS.

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(c) using ln (P2/P1) = (ΔH/R)(1/T2 - 1/T1)

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P298 K = 0.529 atm

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