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Ad libitum [116K]
2 years ago
9

As an athlete exercises, sweat is produced and evaporated to help maintain a proper body temperature. On average, an athlete los

es approximately 307 g of sweat during an hour of exercise. How much energy is needed to evaporate the sweat that is produced? The heat of vaporization for water is 2257J/g. energy required:
Chemistry
1 answer:
dmitriy555 [2]2 years ago
7 0

<u>Answer:</u> For the given amount of sweat lost, the amount of energy required will be 692,899 Joules.

<u>Explanation:</u>

We are given:

Heat of vaporization for water = 2257 J/g

Amount of sweat lost = 307 grams

Applying unitary method:

For 1 g of sweat lost, the energy required is 2257 Joules

So, for 307 grams of sweat lost, the energy required will be = \frac{2257J}{1g}\times 307g=692,899J

Hence, for the given amount of sweat lost, the amount of energy required will be 692,899 Joules.

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Answer:

The correct answer is Option

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Explanation: Mixture is solution which is made of two or more than two substances which are combined only physically not chemically. There are two types of mixture i. e. Homogeneous mixture and heterogeneous mixture. Homogeneous mixture is a mixture in which the substances which are combined are uniform in appearance and heterogeneous mixture is a mixture in which substances are suspended in the solution and easily differentiated.

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The lowest possible concentration of free hydrogen ions is represented by a ph value of
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PH is the logarithmic measure of the concentration of hydrogen ions in solution. In an aqueous system, the lowest possible concentration of H+ ions (least acidic) is 1x 10^-14. The -log(1x10^-14) = pH of 14
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17) A 0.20 M solution of HCl with a volume of 15.0 mL is exactly neutralized by the 0.10 M solution of NaOH with what volume? HI
galina1969 [7]

Answer: A 0.20 M solution of HCl with a volume of 15.0 mL is exactly neutralized by the 0.10 M solution of NaOH with 3 mL volume.

Explanation:

Given: M_{1} = 0.20 M,      V_{1} = 15.0 mL

M_{2} = 0.10 M,            V_{2} = ?

Formula used is as follows.

M_{1}V_{1} = M_{2}V_{2}

Substitute the values into above formula s follows.

M_{1}V_{1} = M_{2}V_{2}\\0.20 M ]times 15.0 mL = 0.10 M ]times V_{2}\\V_{2} = 30 mL

Thus, we can conclude that a 0.20 M solution of HCl with a volume of 15.0 mL is exactly neutralized by the 0.10 M solution of NaOH with 3 mL volume.

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In a neutralization reaction, an aqueous solution of an arrhenius acid reacts with an aqueous solution of an arrhenius base to p
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An aqueous solution of an arrhenius acid reacts with an aqueous solution of an arrhenius base to produce water and salt.

<h3>What is a Salt?</h3>

This is a compound which is formed as a result of a neutralization reaction between acid and base.

Arrhenius acid reacts with an aqueous solution of an arrhenius base to produce water and salt due to increased concentration of H+ and OH- respectively.

Read more about Salt here brainly.com/question/13818836

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2 years ago
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