The most common reaction that causes spoilage isn't a reaction at all. Molds and Bacteria are attracted to the easily found presence of water in the fruit. They find a natural place to reproduce and what they do causes spoilage.
Very few sources talk about the chemical changes that take place. If you put fruit in a refrigerator it slows the spoiling process down. That means that the chemical reaction has to be endothermic (it requires heat to occur)
The process of spoilage is speeded up by bananas for example, giving up Ethylene gas. You do not want to put a banana with tomatoes, because tomatoes are very sensitive to Ethylene. (It's OK to eat them together. They make a terrific salad. Yum).
I cannot find a definitive source that connects all this together, but the conduct of the fruit in refrigerators confirms what I am saying.
Spoilage is a very complex reaction and interaction with the environment. I have given you a hint of what happens but you should search it out to convince yourself of the outcome.
Answer is: formula is Al₂(CO₃)₃.
Aluminium carbonate (Al₂(CO₃)₃) has neutral charge. Because aluminium cation has positive charge 3+ and carbonate anion has negative charge 2-, for right chemical formula, we need two aluminium cations and three carbonate anion:
charge of the molecule = 2 · (3+) + 3 · (-2).
charge of the molecule = 0.
Answer:
A) 8.00 mol NH₃
B) 137 g NH₃
C) 2.30 g H₂
D) 1.53 x 10²⁰ molecules NH₃
Explanation:
Let us consider the balanced equation:
N₂(g) + 3 H₂(g) ⇄ 2 NH₃(g)
Part A
3 moles of H₂ form 2 moles of NH₃. So, for 12.0 moles of H₂:
![12.0molH_{2}.\frac{2molNH_{3}}{3molH_{2}} =8.00molNH_{3}](https://tex.z-dn.net/?f=12.0molH_%7B2%7D.%5Cfrac%7B2molNH_%7B3%7D%7D%7B3molH_%7B2%7D%7D%20%3D8.00molNH_%7B3%7D)
Part B:
1 mole of N₂ forms 2 moles of NH₃. And each mole of NH₃ has a mass of 17.0 g (molar mass). So, for 4.04 moles of N₂:
![4.04molN_{2}.\frac{2molNH_{3}}{1molN_{2}} .\frac{17.0gNH_{3}}{1molNH_{3}} =137gNH_{3}](https://tex.z-dn.net/?f=4.04molN_%7B2%7D.%5Cfrac%7B2molNH_%7B3%7D%7D%7B1molN_%7B2%7D%7D%20.%5Cfrac%7B17.0gNH_%7B3%7D%7D%7B1molNH_%7B3%7D%7D%20%3D137gNH_%7B3%7D)
Part C:
According to the <em>balanced equation</em> 6.00 g of H₂ form 34.0 g of NH₃. So, for 13.02g of NH₃:
![13.02gNH_{3}.\frac{6.00gH_{2}}{34.0gNH_{3}} =2.30gH_{2}](https://tex.z-dn.net/?f=13.02gNH_%7B3%7D.%5Cfrac%7B6.00gH_%7B2%7D%7D%7B34.0gNH_%7B3%7D%7D%20%3D2.30gH_%7B2%7D)
Part D:
6.00 g of H₂ form 2 moles of NH₃. An each mole of NH₃ has 6.02 x 10²³ molecules of NH₃ (Avogadro number). So, for 7.62×10⁻⁴ g of H₂:
![7.62 \times 10^{-4} gH_{2}.\frac{2molNH_{3}}{6.00gH_{2}} .\frac{6.02\times 10^{23}moleculesNH_{3} }{1molNH_{3}}=1.53\times10^{20}moleculesNH_{3}](https://tex.z-dn.net/?f=7.62%20%5Ctimes%2010%5E%7B-4%7D%20gH_%7B2%7D.%5Cfrac%7B2molNH_%7B3%7D%7D%7B6.00gH_%7B2%7D%7D%20.%5Cfrac%7B6.02%5Ctimes%2010%5E%7B23%7DmoleculesNH_%7B3%7D%20%20%7D%7B1molNH_%7B3%7D%7D%3D1.53%5Ctimes10%5E%7B20%7DmoleculesNH_%7B3%7D)
Saliva's buffering capacity and flow of secretion are directly related to the rate and extent of demineralization. ... Saliva can act as a replenishing source and inhibit tooth demineralization during periods of low pH, while promoting tooth remineralization when the pH returns to a neutral state.