All categories

2 years ago

A known number of moles of gas is placed in the flexible container below

Chemistry

2 answers:

musickatia [10]2 years ago

8 0

Answer:2

Explanation:

DIA [1.3K]2 years ago

8 0

Answer:

It's the volume will increase

Explanation:

You might be interested in

Which of the following groups of atoms are most likely to have similar properties?

vladimir1956 [14]

The third option because the elements mentioned in that selection are in the same group, they must have similar properties.

3 0

2 years ago

Read 2 more answers

At 500 K the reaction 2 NO(g) + Cl2(g) ⇌ 2 NOCl(g) has Kp = 51 In an equilibrium mixture at 500 K, the partial pressure of NO is

Aleks [24]

Answer:

p3=0.36atm (partial pressure of NOCl)

Explanation:

2 NO(g) + Cl2(g) ⇌ 2 NOCl(g) Kp = 51

lets assume the partial pressure of NO,Cl2 , and NOCl at eequilibrium are P1 , P2,and P3 respectively

$Kp=\frac{[NOCl]^{2} }{[NO]^{2} [Cl_2] }$

$Kp=\frac{[p3]^{2} }{[p1]^{2} [p2] }$

p1=0.125atm;

p2=0.165atm;

p3=?

Kp=51;

On solving;

p3=0.36atm (partial pressure of NOCl)

7 0

3 years ago

A piece of tin has a mass of 16.52 g and a volume of 2.26 cm2 what is the density of tin?

ioda

M/V=D
16.52/2.26=D
Density=6.86 g/cm^3

8 0

2 years ago

A 40.0-L sample of fluorine is heated from 90.0°C to 186.0°C. What volume will the sample occupy at the higher temperature?

jasenka [17]

Answer:

The volume will be 82.67 L

Explanation:

Charles's Law is the relationship between the volume and temperature of a certain amount of ideal gas. In this way, Charles's law is a law that says that when the amount of gas and pressure are kept constant, the ratio between volume and temperature will always have the same value:

$\frac{V}{T} = k$

Having a certain volume of gas V1 that is at a temperature T1 at the beginning of the experiment, by varying the volume of gas to a new value V2, then the temperature will change to T2, and it will be true:

$\frac{V1}{T1} =\frac{V2}{T2}$

In this case, you know:

V1= 40 L
T1= 90 °C
V2= ?
T2= 186 °C

Replacing:

$\frac{40L}{90C} =\frac{V2}{186 C}$

Solving:

$V2=\frac{40L}{90C} *186 C$

V2= 82.67 L

<u><em>The volume will be 82.67 L</em></u>

5 0

3 years ago

A second reaction mixture was made up in the following way:

Leya [2.2K]

A. We can calculate the initial concentrations of each by the formula:

initial concentration ci = initial volume * initial concentration / total mixture volume

where,

total mixture volume = 10 mL + 20 mL + 10 mL + 10 mL = 50 mL

ci (acetone) = 10 mL * 4.0 M / 50 mL = 0.8 M

ci (H+) = 20 mL * 1.0 M / 50 mL = 0.4 M (note: there is only 1 H+ per 1 HCl)

ci (I2) = 10 mL * 0.0050 M / 50 mL = 0.001 M

B. The rate of reaction is determined to be complete when all of I2 is consumed. This is signified by complete disappearance of I2 color in the solution. The rate therefore is:

rate of reaction = 0.001 M / 120 seconds

rate of reaction = 8.33 x 10^-6 M / s

6 0

3 years ago