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LiRa [457]
3 years ago
7

What is the relationship between elements ,atoms ,and compounds

Chemistry
2 answers:
Svetach [21]3 years ago
8 0
Elements are separate particles that contain the properties of only one type of element (pure substance) and an atom represents that element as the smallest non divisible particle that retains the properties of that element. Compounds can be formed by conjoining different atoms together in different ratios and shapes, so a combination of elements.
garri49 [273]3 years ago
8 0
Elements are pure substances made up of only one kind of atom, they are pure substances. Compounds are made up of two or more elements chemically combined, and all of those have atoms. 
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How am I ment to label this diagram
lora16 [44]
I believe you have to label out the positive metal ion and the delocalized electrons. They're the 2 things that makes up a metal structure.

In the diagram, the circles with the + symbol are the positive metal ions, since + represents positive. And the remaining - circles are the delocalized electrons, as electrons are negative.

And for how a metal conducts electricity, since they're delocalized mobile electrons present in any metal structures, they're able to move away from the metal to the positive side of the battery and more electrons can replace their place flowing from the negative side.
5 0
3 years ago
A block of ice is cooled from -0.5 degrees Celsius to -10.1 degrees Celsius. Calculate the temperature change, delta T, in degre
ss7ja [257]
Delta T= T final - T initial
Tfinal= -101.1 °C
Tinitial= -0.5 °C
•Delta T = -101.1°C - (-0.5°C)
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3 0
3 years ago
What is the mass (grams) of salt in 10.0 m' of ocean water? ball park-4x10's (1.000 molsalt -58.44 g salt, 1.0 L ocean water -0.
koban [17]

Answer:

3.5 × 10⁵ g of salt

Explanation:

<em>What is the mass (grams) of salt in 10.0 m³ of ocean water?</em>

We have this data:

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  • 1.0 L of ocean water contains 0.60 mol of salt

We will need the following relations:

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  • 1 m³ = 10³ dm³

We can use proportions:

10.0m^{3} .\frac{10^{3}dm^{3}  }{1m^{3} } .\frac{1L}{1dm^{3} } .\frac{0.60molSalt}{1.0L} .\frac{58.44gSalt}{1molSalt} =3.5 \times 10^{5} gSalt

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4 0
3 years ago
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Which kind of investigations allow for the control of variables?
Butoxors [25]

Answer:

the answer to this is O hypothesis

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3 years ago
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