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3 years ago

What is the relationship between elements ,atoms ,and compounds

2 answers:

8 0

Elements are separate particles that contain the properties of only one type of element (pure substance) and an atom represents that element as the smallest non divisible particle that retains the properties of that element. Compounds can be formed by conjoining different atoms together in different ratios and shapes, so a combination of elements.

garri49 [273]3 years ago

8 0

Elements are pure substances made up of only one kind of atom, they are pure substances. Compounds are made up of two or more elements chemically combined, and all of those have atoms.

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A man weighing 75 kg takes 5 minutes to reach a height of 5 m when he climbs a staircase. What is his power?

Naddika [18.5K]

Answer: B. 12.25 W

please give brainliest!

Explanation:

1) Force = Weight = 75 x 9.8 = 735 N

2.)Work = Force x Height = 735 x 5 = 3675 J

3.)Power = Work / Time = 3675 / (5 x 60) = 12.25 W

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3 years ago

Comets are mixtures of frozen gases, rocks, and dust. <br><br> True or False?

Alika [10]

Hi, I am Rosy67 and im here to help.

I have read your sentence and i believe the answer is the following;

True.

Hope this could help!!!!!

~Rosy67

(PS, Can i have brainliest? Im trying to level up) :) *_*

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4 years ago

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Aleks04 [339]

Answer:

THE GOD ALMIGHTY!

Explanation:

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3 years ago

According to the hypothesis the solar system formed from a cloud of dust and gas

katrin2010 [14]

I assume this is a true or false question. I would say true

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3 years ago

Read 2 more answers

Calcium hydroxide, Ca(OH)2, is an ionic compound with a solubility product constant, Ksp, of 6.5×10–6. Calculate the solubility

kari74 [83]

Answer: The solubility of this compound in pure water is 0.012 M

Explanation:

Solubility product is defined as the equilibrium constant in which a solid ionic compound is dissolved to produce its ions in solution. It is represented as $K_{sp}$

The equation for the ionization of the is given as:

$Ca(OH)_2\rightarrow Ca^{2+}+2OH^-$

By stoichiometry of the reaction:

1 mole of $Ca(OH)_2$ gives 1 mole of $Ca^{2+}$ and 2 mole of $OH^-$

When the solubility of $Ca(OH)_2$ is S moles/liter, then the solubility of $Ca^{2+}$ will be S moles\liter and solubility of $OH^-$ will be 2S moles/liter.

$K_{sp}=[Ca^{2+}][OH^{-}]^2$

$6.5\times 10^{-6}=[S][2S]^2$

$S=0.012M$

Thus solubility of this compound in pure water is 0.012 M

5 0

3 years ago