Answer:
C.) 5, 12, 13
Step-by-step explanation:
In a right triangle, the sum of the squares of the two shorter sides must equal the square of the longest side (Pythagoras).
a² + b² = c²
We can test each set of numbers to see which one fits.
A.) 8² + 12² = 16²
64 + 144 = 256
208 ≠ 256
B.) 6² + 7² = 8²
36 + 49 = 64
85 ≠ 64
C.) 5² + 12² = 13²
25 + 144 = 169
169 = 169
The numbers 5, 12, and 13 could represent the lengths of the sides of a right triangle.
D.) 16² + 32² = 36²
256 + 1024 = 1296
1280 ≠ 1296
Answer:
- North Middle School = 10 students
- Central Middle School = 6 students
- South Middle School = 4 students
Step-by-step explanation:
First calculate the total number of students in all the schools:
= 618 + 378 + 204
= 1,200 students
Use this number to calculate the proportion of the total population that a school so that this can then be used to determine the proportion of the 20 delegates they should sent.
North Middle school:
= 618/1,200 * 20
= 10 students
Central Middle School:
= 378 / 1,200 * 20
= 6 students
South Middle School:
= 204/1,200 * 20
= 4 students
Answer: A- 2/3
Step-by-step explanation:
Possible outcomes when a coin is tossed 3 times is 1/2 + 1/2+ 1/2= 3/2
Probability of getting exactly one tail=
3/2x=1
x=1÷3/2
=1 ×2/3
=2/3
He got 4 percent right. 16 percent of 15 is 4 :)
Answer:
The probability of getting two heads and a four is 1/24
Step-by-step explanation:
The probability of getting a head upon a single toss of a coin, assuming the coin is fair is 1/2.
The probability of getting two heads upon tossing two coins together will simply be the product of the individual probabilities;
P (HH) = 1/2 * 1/2 = 1/4
On the other hand, the probability of getting a four upon rolling a six sided number cube is;
1/6
This is because the number 4 occurs only once in a total possible of 6 numbers.
Therefore, the probability of getting two heads and a four;
P (HH4) = 1/2 * 1/2 * 1/6 = 1/24 since the three events are independent.
