Answer:
Phenotypic ratio - 3 Freckes : 1 No freckles
Explanation:
This question represents a monohybrid cross i.e. involving a single gene coding for possession or not of freckles. The allele for possession of freckles (F) is dominant over the allele for no freckles (f).
In a cross between two HETEROZYGOUS parents i.e. Ff × Ff, each parent will produce gametes with alleles F and f respectively. Using a punnet square (see attached image), four possible offsprings will be produced with genotypes: FF, Ff, Ff and ff.
Based on this genotypes, the phenotypic ratio of the offsprings will be 3:1 where 3 offsprings will possess freckles and 1 will have no freckles.
Answer: Carbon dioxide + Water Glucose (sugar) + Oxygen CO2 + H2O C6H12O6 + 6O2
Explanation:
Carbon dioxide + Water Glucose (sugar) + Oxygen CO2 + H2O C6H12O6 + 6O2 Cellular respiration or aerobic respiration is a series of chemical reactions which begin with the reactants of sugar in the presence of oxygen to produce carbon dioxide and water as waste products.
Only carbohydrates are broken down into which of the following subunits
- <u>SUGARS</u>
Answer:D
Explanation: The pulmonary air sacs of birds only permit a unidirectional flow of air through the lungs. Unidirectional flow means that air is inhale and exhale through one trachea alternatively. This means the bird lungs only receive largely fresh air which has a high oxygen content during inhalation and do not receive fresh during exhalation. While air flow bidirectional in mammals.
MITOSIS results in the formation of a new cells with a full set of chrimosomes
