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faltersainse [42]
3 years ago
9

Can anyone help and explain the answer ?

Mathematics
1 answer:
Readme [11.4K]3 years ago
3 0

Answer:

X=65

Step-by-step explanation:

The picture is not very good, but i guess tht x is angle on the section. Right?

If it is true we have that:

The angle formed by two intersection chode is:

X=1/2(30+100)

X=130/2

X=65

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Complete Question

The  complete question is shown on the first uploaded image  

Answer:

The interval is  -0.0037 < p_1-p_2

Step-by-step explanation:

From the question we are told that

   The first  sample size is  n _1 =  1068000

    The  first sample proportion is \r p_1  =  0.089

    The  second sample  size is  n_2  =  1476000

    The  second sample proportion is  \r p_2 =  0.092

   

Given that the confidence level is  95% then the level of significance is mathematically evaluated as

             \alpha  =  (100 - 95 )\%

              \alpha  =  0.05

Next we obtain the critical value  of  \frac{\alpha }{2}  from the normal distribution table  

The value is  

               Z_{\frac{\alpha }{2} } =z_c=  1.96

Generally the 95% confidence interval is mathematically represented as

       (\r p_1 -  \r p_2  ) -z_c \sqrt{ \frac{\r p_1 \r q_1 }{n_1}  + \frac{\r p_2 \r q_2 }{n_2}} < (p_1 - p_2 )  <  (\r p_1 -  \r p_2  ) +z_c \sqrt{ \frac{\r p_1 \r q_1 }{n_1}  + \frac{\r p_2 \r q_2 }{n_2}}

Here  \r q_1 is mathematically evaluated as \r q_1  = (1 - \r p_1)= 1-0.089 =0.911

and  \r q_2  is mathematically evaluated as  \r q_2 = (1 -  \r p_2) =  1-  0.092 =  0.908

So

       (0.089 -  0.092 ) -1.96 \sqrt{ \frac{0.089* 0.911 }{1068000}  + \frac{0.092* 0.908 }{1476000}} < (p_1 - p_2 )  < (0.089 -  0.092 ) +1.96 \sqrt{ \frac{0.089* 0.911 }{1068000}  + \frac{0.092* 0.908 }{1476000}}

-0.0037 < p_1-p_2

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