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3 years ago

What voltage is applied to a 20 ohm fixed resistor if the current through the resistor is 1.5 amps?

Physics

1 answer:

pantera1 [17]3 years ago

5 0

Answer:

SDFK fbsdfasdgasdfgasdfg⊃⊃⊃⊃⊃⊃×∈⇔⇔⇔

Explanation:

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Create a file "parts_inv.dat" that stores on each line a part number, cost, and quantity in inventory, in the following format:1

andriy [413]

Answer:

%Open the file.

fID = fopen('parts_inv.dat');

%Read from the file.

data = fscanf(fID,'%d\t%f\t%d',[3,inf]);

%Close

fclose(fID);

%Restore the data.

data = data';

%Get the size

[rs, cs] = size(data);

%Set value.

invCost = 0;

%Loop

for rw = 1 : rs

%Find cost

invCost = invCost + (data(rw, 2) * data(rw, 3));

%Loop end

end

%Display the cost.

fprintf('Total cost: %4.2f\n\n', invCost);

Explanation:

7 0

3 years ago

3.88 milligrams is equal to how many centigrams?

Lana71 [14]

1 centigram is equal to 10 milligrams.

Divide 3.88 milligrams by 10 to convert into centigrams.

3.88 / 10 = .388

The answer is .388 centigrams.

3 0

3 years ago

Read 2 more answers

How fast is the sixth cosmic velocity?

denpristay [2]

<span>25,000 miles per hour

hope that this helps</span>

3 0

2 years ago

Through what vertical height is a 50 N object moved if 250 J of work is done lifting it against the gravitational field of Earth

zimovet [89]

Explanation:

Given parameters:

Weight of object = 50N

Work done in lifting object = 250J

Unknown:

Vertical height = ?

Solution:

The work done on an object is the force applied to lift a body in a specific direction.

Work done = force x distance

Weight is a force in the presence of gravity;

Work done = weight x height of lifting

Height of lifting = $\frac{work done }{weight}$

Height of lifting = $\frac{250}{50}$ = 5m

The vertical height through which the object was lifted is 5m

learn more:

Work done brainly.com/question/9100769

#learnwithBrainly

6 0

2 years ago

Ill give 15 points to the one who helps me with this

alexandr402 [8]

Machenical number one

6 0

3 years ago