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ankoles [38]
4 years ago
6

What voltage is applied to a 20 ohm fixed resistor if the current through the resistor is 1.5 amps?

Physics
1 answer:
pantera1 [17]4 years ago
5 0

Answer:

SDFK fbsdfasdgasdfgasdfg⊃⊃⊃⊃⊃⊃×∈⇔⇔⇔

Explanation:

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The number 14 is the 'mass number'. What does it tell us about this isotope?​
Svetradugi [14.3K]

Answer:

This show the most stable of atom of that element

Explanation:

The mass number of a element on the periodic table show the most stable atoms of that element.

4 0
3 years ago
If you throw an apple towards the sky why its going up in spite of gravitational pull? .
Paul [167]

Answer:

due to tension force acting against gravitational pull

Explanation:

hope this somewhat helps :)

4 0
3 years ago
Ok plz answer and tell me how to do it
kirza4 [7]
Answer: 25N

method: total force in the right hand direction is 100N and total force in the left hand direction is 125N. To get the net force, we add forces if they are in the same direction and substract if they are in opposite directions. since 100N and 125N are in opposite directions, we substract the larger value from the smaller value. Then we get 25N in the left hand direction as the final answer.
4 0
4 years ago
A student throws a heavy red ball horizontally from a balcony of a tall building with an initial speed v0. At the same time, a s
liraira [26]

Without air resistance, both balls reach the ground at the same instant.

Neither horizontal motion nor weight affects vertical motion.

6 0
4 years ago
The amount of energy that must be absorbed or lost to raise or lower the temperature of 1 g of liquid water by 1°c _____.
Fiesta28 [93]

Answer:

4.2 J

Explanation:

Specific heat capacity: This is defined as the amount of a heat required to rise a unit mass of a substance through a temperature of 1 K

From specific heat capacity,

Q = cmΔt.............................. Equation 1

Where Q = amount of energy absorbed or lost, c = specific heat capacity of water, m = mass of water, Δt = Temperature rise.

Given: m = 1 g = 0.001 kg, Δt = 1 °C

Constant : c = 4200 J/kg.°C

Substitute into equation 1

Q = 0.001×4200(1)

Q = 4.2 J.

Hence the energy absorbed or lost = 4.2 J

6 0
4 years ago
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