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arlik [135]
4 years ago
8

Solve for y.

Mathematics
2 answers:
tia_tia [17]4 years ago
5 0

Answer:

its actually 18.2 not just 18 cause i took the test

Step-by-step explanation:

so im right!!!!!

Svetradugi [14.3K]4 years ago
4 0
1. For y, I think that refers to the first picture attached. As you can see, each side of the triangle have the same short line drawn across it. It means that they are equal in length. That means the triangle is equilateral, which means each interior angle is 60°. Thus,

60 = 5y + 10
5y = 60 - 10
5y = 50
y = 50/5 =<em> 10</em>

2. As you can see in the second picture attached, Angles B and C are equal. That also means that their respective opposite sides are equal. So,

8x - 4 = 5x + 11
8x - 5x = 11 + 4
3x = 15
x = 15/3 = 5

Consequently,
BC = 4x - 2
BC = 4(5) - 2 = <em>18</em>
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nika2105 [10]

The rules are

x^a\cdot x^b = x^{a+b}

\dfrac{x^a}{x^b} = x^{a-b}

Let me show you why with a couple of examples: suppose we want to multiply

4^3\cdot 4^2

Since powers are just repeated multiplications, we have

4^3\cdot 4^2 = \underbrace{4\cdot 4\cdot 4}_{4^3}\cdot\underbrace{4\cdot 4}_{4^2}=4^5 = 4^{3+2}

Similarly, we have

\dfrac{4^3}{4^2} = \dfrac{4\cdot 4 \cdot 4}{4\cdot 4} = 4 = 4^1 = 4^{3-2}

8 0
3 years ago
Which statement correctly describes the end behavior of the function f ( x ) = − x 2 + 3 x + 12
Yuri [45]
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3 years ago
9a + 8 - 20-3-50<br> Answer
dem82 [27]

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Step-by-step explanation:

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5 0
3 years ago
Solve the equation by graphing. If exact roots cannot be found, state the consecutive integers between which the roots are locat
zavuch27 [327]

Answer:

The equation contains exact roots at x = -4 and x = -1.

See attached image for the graph.

Step-by-step explanation:

We start by noticing that the expression on the left of the equal sign is a quadratic with leading term x^2, which means that its graph shows branches going up. Therefore:

1) if its vertex is ON the x axis, there would be one solution (root) to the equation.

2) if its vertex is below the x-axis, it is forced to cross it at two locations, giving then two real solutions (roots) to the equation.

3) if its vertex is above the x-axis, it will not have real solutions (roots) but only non-real ones.

So we proceed to examine the vertex's location, which is also a great way to decide on which set of points to use in order to plot its graph efficiently:

We recall that the x-position of the vertex for a quadratic function of the form f(x)=ax^2+bx+c is given by the expression: x_v=\frac{-b}{2a}

Since in our case a=1 and b=5, we get that the x-position of the vertex is: x_v=\frac{-b}{2a} \\x_v=\frac{-5}{2(1)}\\x_v=-\frac{5}{2}

Now we can find the y-value of the vertex by evaluating this quadratic expression for x = -5/2:

y_v=f(-\frac{5}{2})\\y_v=(-\frac{5}{2} )^2+5(-\frac{5}{2} )+4\\y_v=\frac{25}{4} -\frac{25}{2} +4\\\\y_v=\frac{25}{4} -\frac{50}{4}+\frac{16}{4} \\y_v=-\frac{9}{4}

This is a negative value, which points us to the case in which there must be two real solutions to the equation (two x-axis crossings of the parabola's branches).

We can now continue plotting different parabola's points, by selecting x-values to the right and to the left of the x_v=-\frac{5}{2}. Like for example x = -2 and x = -1 (moving towards the right) , and x = -3 and x = -4 (moving towards the left.

When evaluating the function at these points, we notice that two of them render zero (which indicates they are the actual roots of the equation):

f(-1) = (-1)^2+5(-1)+4= 1-5+4 = 0\\f(-4)=(-4)^2+5(-4)_4=16-20+4=0

The actual graph we can complete with this info is shown in the image attached, where the actual roots (x-axis crossings) are pictured in red.

Then, the two roots are: x = -1 and x = -4.

5 0
3 years ago
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