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mamaluj [8]
3 years ago
13

Find the percent of decrease from 340 to 260. Round to the nearest tenth of a percent if necessary.

Mathematics
2 answers:
Marina CMI [18]3 years ago
8 0

To get the solution, we are looking for, we need to point out what we know.


1. We assume, that the number 340 is 100% - because it's the output value of the task.

2. We assume, that x is the value we are looking for.

3. If 100% equals 340, so we can write it down as 100%=340.

4. We know, that x% equals 260 of the output value, so we can write it down as x%=260.

5. Now we have two simple equations:

1) 100%=340

2) x%=260

where left sides of both of them have the same units, and both right sides have the same units, so we can do something like that:

100%/x%=340/260

6. Now we just have to solve the simple equation, and we will get the solution we are looking for.


7. Solution for 260 is what percent of 340


100%/x%=340/260

(100/x)*x=(340/260)*x - we multiply both sides of the equation by x

100=1.30769230769*x - we divide both sides of the equation by (1.30769230769) to get x

100/1.30769230769=x

76.4705882353=x

x=76.4705882353


now we have:

260 is 76.4705882353% of 340

hram777 [196]3 years ago
7 0
Fund the difference between the two numbers
340-260=80
divide 80 by 340
0.24
multiply by 100
24% (percent of decrease)
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============================================================

Explanation:

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So,

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3 years ago
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Answer:

25 seconds

Step-by-step explanation:

Hi there!

In order to answer this question, first we need to know how many bolts per second are produced by each machine, this can be known by dividing the number of bolts by the time it takes.

For machine A:

A = \frac{120 bolts}{40 s}= 3 \frac{bolts}{s}

For machine B:

B = \frac{100 bolts}{20 s}= 5 \frac{bolts}{s}

So, if the two machines run simultaneously, we will have a rate of prodcution of bolts equal to the sum of both:

A+B=(3+5)\frac{bolts}{s}=8\frac{bolts}{s}

Now, we need to know how much time it will take to producee 200 bolts, to find this out we need to divide the amount of bolts by the production rate:

t = \frac{bolts}{ProductionRate}= \frac{200 bolts}{8 \frac{bolts}{s} }

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t = \frac{200}{8} s = 25 s

So it will take 25 seconds to produce 200 bolts with machine A and B running simultaneously.

Greetings!

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5 0
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Please help! Thanks in advance!!
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