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3 years ago

Which vector has an x-component with a length of 4?

Physics

1 answer:

zepelin [54]3 years ago

7 0

Answer:

C.) vector C

Explanation:

From the graph provided:

Four vectors are present :

Vectors a, b, c and d.

The x-component of the vector is its magnitude along the x-axis.

Taking the coordinate of each vector:

Vector a = (1,4) : length of x- component = 1

Vector b = (1, 1) : length of x- component = 1

Vector c = (4, -4) : length of x- component = 4

Vector d = (-3, 4) : length of x- component = - 3

Therefore, vector c has an x-component length of 4

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A solid disk rotates in the horizontal plane at an angular velocity of 0.649 rpm with respect to an axis perpendicular to the di

77julia77 [94]

Answer:

The angular velocity of the disk is 0.0369 rad/sec.

Explanation:

Convert 0.649 rpm to rad/s

0.649 rpm = 0.649 * (2π/60) = 0.0679rad/sec

From the question,

Summation of final angular momentum equals summation of initial angular momentum

I*w = Io*wo

w = wo (lo/I)

But I = Isand + Io

and Isand = Msand * R²sand

Therefore, w = wo (lo/I) = wo (Io/Msand * R²sand + Io)

Where,

wo = 0.0679rad/sec

Io = 0.101 kg m2

Msand = 0.499 kg

Rsand = 0.415 m

Hence,

w = 0.0679 {0.101/(0.499*(0.415)²+0.101)}

w = 0.0679 (0.101/0.1869)

w = 0.0679*0.544 = 0.0369 rad/sec

The angular velocity of the disk is 0.0369 rad/sec.

5 0

3 years ago

Only conservative forces perform work on an object over a span of time. During this time, the total mechanical energy of the obj

siniylev [52]

During this time, the total mechanical energy of the object remains constant.

Answer: Option C

<u>Explanation:</u>

The sum total of potential energy and the kinetic energy presented in the system is called mechanical energy. The total mechanical energy in the system, which represents the combined potential and kinetic energies, remains constant as long as the only force work at conservative forces, and mechanical energy is maintained on this principle.

For example, a gravity box in which we throw the ball straights up, and then leave the hand with a specific amounts of kinetic energy. In the first half of the track, there is no kinetic energy, but it has potential energy similar to kinetic energy that it had when that left our hand. When we catch that again, it has the same kinetic energy as when that left our hand. That is why gravity belongs to the category of conservative forces.

4 0

4 years ago

True or False: Primary and secondary succession both end with the formation of a climax community.

jolli1 [7]

Answer: true

Explanation: Ecological succession, the process by which the structure of a biological community evolves over time. Two different types of succession primary and secondary have been distinguished The final stage of succession is a climax community, which is a very stable stage that can endure for hundreds of years.

6 0

3 years ago

When Kevin pulls his cotton shirt off his body, the electrons get transferred from the (shirt or body) to the (shirt or body) .

Masja [62]

<span>When Kevin pulls his cotton shirt off his body, the electrons get transferred from the shirt (in form of static charges i.e. electrons to the body. So, the shirt becomes positively charged and Kevin’s body becomes negatively charged.

As a result of charge transfer from the shirt to the body, we can hear a crackling sound. or if observed in dark, a sparkle can be seen.</span>

6 0

3 years ago

A 70.0 kg70.0 kg ice hockey goalie, originally at rest, has a 0.170 kg0.170 kg hockey puck slapped at him at a velocity of 41.5

Elza [17]

Answer:

0.2012 m/s

- 41.3 m/s

Explanation:

M = mass of ice hockey goalie = 70 kg

V = initial velocity of the hockey goalie = 0 m/s

V' = final velocity of hockey goalie after collision = ?

m = mass of hockey puck = 0.170 kg

v = initial velocity of hockey puck = 41.5 m/s

v' = final velocity of hockey puck = ?

Using conservation of momentum

M V + m v = M V' + m v'

(70) (0) + (0.170) (41.5) = (70) V' + (0.170) v'

7.055 = (70) V' + (0.170) v'

V' = 0.1008 - 0.00243 v' eq-1

Using conservation of kinetic energy

(0.5) M V² + (0.5) m v² = (0.5) M V'² + (0.5) m v'²

M V² + m v² = M V'² + m v'²

(70) (0)² + (0.170) (41.5)² = (70) V'² + (0.170) v'²

292.8 = (70) V'² + (0.170) v'²

Using eq-1

292.8 = (70) (0.1008 + 0.00243 v')² + (0.170) v'²

v' = - 41.3 m/s

Using eq-1

V' = 0.1008 - 0.00243 v'

V' = 0.1008 - 0.00243 (- 41.3)

V' = 0.2012 m/s

6 0

4 years ago