On the change in potential energy
Answer:
Explanation:
Let equal mass of Ne and Kr be m gm
no of moles of Ne and Kr will be m / 20 and m / 84 ( atomic weight of Ne and Kr is 20 and 84 )
Let the pressure and volume of both the gases be P and V respectively .
The temperature of Ne be T₁ and temperature of Kr be T₂.
For Ne
PV = (m / 20) x R T₁
For Kr
PV = (m / 84) x R T₂
T₁ / T₂ = 84 / 20
We know that
average KE of an atom of mono atomic gas = 3 / 2 x k T
k is boltzmann constant and T is temperature .
KEKr/KENe = T₂ / T₁
= 20 / 84
The correct answer is A continúe moving with constant velocity
