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4 years ago

What happens when light rays pass through a concave lens?

Physics

2 answers:

kipiarov [429]4 years ago

7 0

Answer:

Its A

Explanation:

Alexxx [7]4 years ago

4 0

Answer:

Concave lenses are thinner at the middle. Rays of light that pass through the lens are spread out (they diverge). A concave lens is a diverging lens. When parallel rays of light pass through a concave lens the refracted rays diverge so that they appear to come from one point called the principal focus.

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A ball is projected upward at time t = 0.0 s, from a point on a roof 70 m above the ground. The ball rises, then falls and strik

pentagon [3]

Answer:

The velocity of a ball will be "-70.13 m/s".

Explanation:

The given values are:

u = 70 m

t = 0.0 s

g = a = -9.8 m/s²

s = -1 m

v = ?

As we know,

The equation of motion will be:

⇒ $v^2-u^2=2as$

On substituting the estimated values, we get

⇒ $v^2-(70)^2=2\times (-9.8)\times (-1)$

⇒ $v^2-4900=19.6$

⇒ $v^2=19.6+4900$

⇒ $v^2=4919.6$

⇒ $v=\sqrt{4919.6}$

⇒ $v=70.13 \ m/s$

In downward direction, it will be:

⇒ $v=-70.13 \ m/s$

8 0

3 years ago

How do organisms interact with each other?

satela [25.4K]

Answer:

They interact in a lot of ways, prey, predator, etc.

6 0

3 years ago

A runner moves 2.88 m/s north. She accelerates at 0.350 m/s^2 at a -52.0 angle. At the point in the motion where she is running

MrRissso [65]

The runner has initial velocity vector

$\vec v_0=\left(2.88\dfrac{\rm m}{\rm s}\right)\,\vec\jmath$

and acceleration vector

$\vec a=\left(0.350\dfrac{\rm m}{\mathrm s^2}\right)(\cos(-52.0^\circ)\,\vec\imath+\sin(-52.0^\circ)\,\vec\jmath)$

so that her velocity at time $t$ is

$\vec v=\vec v_0+\vec at$

She runs directly east when the vertical component of $\vec v$ is 0:

$2.88\dfrac{\rm m}{\rm s}+\left(0.350\,\dfrac{\rm m}{\mathrm s^2}\right)\sin(-52.0^\circ)\,t=0\implies t=10.4\,\rm s$

It's not clear what you're supposed to find at this particular time... possibly her position vector? In that case, assuming she starts at the origin, her position at time $t$ would be

$\vec x=\vec v_0t+\dfrac12\vec at^2$