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3 years ago

What happens when light rays pass through a concave lens?

Physics

2 answers:

kipiarov [429]3 years ago

7 0

Answer:

Its A

Explanation:

Alexxx [7]3 years ago

4 0

Answer:

Concave lenses are thinner at the middle. Rays of light that pass through the lens are spread out (they diverge). A concave lens is a diverging lens. When parallel rays of light pass through a concave lens the refracted rays diverge so that they appear to come from one point called the principal focus.

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One end of a 34-m unstretchable rope is tied to a tree; the other end is tied to a car stuck in the mud. The motorist pulls side

anyanavicka [17]

Answer:

Fc = 89.67N

Explanation:

Since the rope is unstretchable, the total length will always be 34m.

From the attached diagram, you can see that we can calculate the new separation distance from the tree and the stucked car H as follows:

L1+L2=34m

$L1^2=L2^2=L^2=2^2+(H/2)^2$ Replacing this value in the previous equation:

$\sqrt{2^2+H^2/4}+ \sqrt{2^2+H^2/4}=34$ Solving for H:

$H=\sqrt{52}$

We can now, calculate the angle between L1 and the 2m segment:

$\alpha = atan(\frac{H/2}{2})=60.98°$

If we make a sum of forces in the midpoint of the rope we get:

$-2*T*cos(\alpha ) + F = 0$ where T is the tension on the rope and F is the exerted force of 87N.

Solving for T, we get the tension on the rope which is equal to the force exerted on the car:

$T=Fc=\frac{F}{2*cos(\alpha) } = 89.67N$

7 0

3 years ago

If a bow holds 500J of potential energy as the arrow is pulled back, how much kinetic energy will the arrow have after it has be

ale4655 [162]

Answer:

500J

Explanation:

The arrow will have an energy of 500J after it has been released from its state of rest.

This is compliance with the law of conservation of energy which states that "in every system, energy is neither created nor destroyed but transformed from one form to another".

The energy at rest which is the potential energy is 500J
This energy will be converted to kinetic energy in total after the arrow has been released.
This way, no energy is lost and we can account for the energy transformations occurring.

4 0

3 years ago

PLS ANSWER ASAP!!

Molodets [167]

b) between poles M1 and M2

Explanation:

From the expression, we can deduce that r is the distance between two magnetic poles M1 and M2.

The law of attraction between two magnetic poles states that:

the force of attraction or repulsion between two magnetic poles is a function of the product of the strength of the magnetic poles and the square of the distance between the poles

Mathematically:

FM = K $\frac{M1 M2}{r^{2} }$

here r is the distance between the poles

FM is the magnetic force between the poles

M1 is the strength of the first magnetic pole

M2 is the strength of the second pole

K is the magnetic field constant

learn more:

magnetic pole brainly.com/question/2191993

#learnwithBrainly

8 0

3 years ago

The x vector component of a displacement vector has a magnitude of 86.2 m and points along the negative x axis. The y vector com

Flauer [41]

Answer:

(a) Magnitude of Vector = 207.73 m

(b) Direction = 65.48°

Explanation:

(a)

The formula to find out the magnitude of a resultant vector with the help of its x and y components is given as follows:

$Magnitude\ of\ Vector = \sqrt{d_{x}^{2} + d_{y}^{2}} = \sqrt{(86.2\ m)^{2} + (189\ m)^{2}}\\\\$

Magnitude of Vector = 207.73 m

(b)

For the direction of the vector we have the formula:

$Direction = tan^{-1}(\frac{y}{x})\\\\Direction = tan^{-1}(\frac{189\ m}{86.2\ m})\\\\$

Direction = 65.48°

4 0

3 years ago

44. ( John weighs 80 kg, and eats a 1,000 J candy bar. If his

Darina [25.2K]

John can run with the velocity of 5 m/s

Explanation:

Kinetic energy is defined as the energy is being used to do an activity, basically energy associated with the motion of objects in the universe.
The formula used to find the kinetic energy of an object is k = $\frac{1}{2} mv^{2}$ where as k represented as kinetic energy, m is the mass of the object and v is the velocity of the given object.

Here, to find the answer we have to re-write the equation as $v = \sqrt[2]{\frac{2 k}{m} }$
Given, the mass of the object, here it is John = 80 kg, energy needs to be converted to kinetic energy, k = 1000 J.
Hence, substitute all the values, then you would velocity as 5 m/s

4 0

4 years ago