Answer:
The force of impact of the water bottle is F = 13,475 N
Explanation:
Given data,
The height of the antenna, h = 275 m
The mass of the 1 L water bottle, m = 1 kg
Let the bottle moves distance immediately after the impact is, d = 0.2 m
The force exerted by the bottle on the bushes at the ground is given by the formula,
F = mgh / d
Substituting the values
F = 1 x 9.8 x 275 / 0.2
= 13,475 N
The value of the force of impact can be reduced by increasing the value of d, it is like the lowering the hand along with the motion of the ball to catch it thereby reduce the force of impact.
The force of impact of the water bottle is F = 13,475 N
The answer is C hope it helps
The word 'apparent' mean in apparent visual magnitude is, how bright the star appears when viewed from Earth.
What is visual magnitude?
The brightness of a celestial body is determined by eye estimation with or without optical aid or by other instrumentation equivalent to the eye in spectral sensitivity.
Apparent magnitude:
- Apparent magnitude is a measure of how bright the star appears when viewed from Earth.
- It is a measure of the brightness of a star or other astronomical object observed from Earth.
- An object's apparent magnitude depends on its intrinsic luminosity and its distance from Earth.
Hence,
The word 'apparent' mean in apparent visual magnitude is, how bright the star appears when viewed from Earth.
Learn more about visual magnitude here:
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The balanced equation of the combustion of the propane is
From the above chemical equation, it is clear that 1 mole of propane requires 5 moles of oxygen to undergo complete combustion as the result of this reaction, 3 moles of carbon-di-oxide and 4 moles of water molecules will be produced.
Therefore one-half mole of propane requires 2.5 moles of oxygen to undergo complete combustion. And in the reaction, 1.5 moles of carbon-di-oxide and 2 moles of water molecules are produced.
Therefore the answer is, 'One-half of propane combines with 2.5 moles of oxygen to produce 2 moles of water and 1.5 moles of carbon dioxide'
As per Newton's II law we know that
here
F = applied unbalanced force
m = mass of object
a = acceleration of object
now it is given that force F = 50 N North applied on block on earth due to which block will accelerate by 4 m/s^2
so here from above equation
Now we took another situation where block is placed on surface of moon and again force F = 25 N is applied on the block
So we will again use Newton's II law
so block will accelerate on moon by acceleration 2 m/s^2
