Answer:
B
Step-by-step explanation:
Answer:
Upper confidence level (UCL) = 29367.875
Lower confidence level (LCL) =23061.064
Step-by-step explanation:
Given : sample mean=26214.47
sample standard deviation=5969.25
sample size=15
degree of freedom=14
t critical value for 94% confidence with 14 degree of freedom=2.046
To Find : Upper confidence level (UCL) =?Lower confidence level (LCL) =?
Solution:
Formula for confidence interval =
sample mean= =26214.47
sample standard deviation = s =5969.25
sample size = n =15
t critical value for 94% confidence with 14 degree of freedom =2.046
Substitute the values in the formula :
confidence interval =
confidence interval = to
confidence interval = to
Hence Upper confidence level (UCL) = 29367.875 and Lower confidence level (LCL) =23061.064
5^6=474245568866432215678654322
If MO bisects angle LMN:
6 x - 20 = 2 x + 36
6 x - 2 x = 36 + 20
4 x = 56
x = 56 : 4
x = 14
∠ LMN = 2 · ( 2 · 14 + 36 ) = 2 · ( 28 + 36 ) = 2 · 64 = 128
Answer : C ) x = 14, ∠ LMN = 128
Answer:
123.077
Step-by-step explanation:
0.39x=48
0.39x/0.39=48/0.39
x=48/0.39
x=123.077