Answer:
(2, 8)
Step-by-step explanation:
Given the system of equation
3x+2y=22 ... *4
-4x+3y=16 .... *3
Using the elimination method
12x + 8y = 88
-12x + 9y = 48
Add
8y + 9y = 88+48
17y = 136
y = 136/17
y = 8
Recall that
3x+2y=22
3x+2(8)=22
3x + 16 = 22
3x = 22-16
3x = 6
x = 6/3
x = 2
Hence the required solution (x, y) is (2, 8)
Answer is C. the third option
Plug in
When x = - 6, y = ∛[-(-6) + 2] = ∛8 = 2
When x = 1, y = ∛[-1 + 2] = ∛1 = 1
When x = 2, y = ∛[-2 + 2] = ∛0 = 0
When x = 3, y = ∛[-3 + 2] = ∛-1 = -1
When x = 10, y = ∛[-10 + 2] = ∛-8 = -2