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AysviL [449]
3 years ago
10

Fill in the table and then round to the given place 225.286

Mathematics
1 answer:
Viefleur [7K]3 years ago
7 0
The answer is 1.4.3. thats the answer rounded
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What is the rounding or compatible number<br><br> of 256+321
Nana76 [90]
<span>Compatible </span>numbers for 256...
1. Rounded to the nearest hundred = 200
2. Rounded to the nearest tens place = 260

Compatible numbers for 321...
1. Rounded to the nearest hundred = 300
2. Rounded to the nearest tens place = 320

I hope this helps! :)


4 0
3 years ago
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Solve 7x-9=28+4(x-1)
ANEK [815]
I got 10.333333333333
8 0
3 years ago
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miss Akunina [59]
B= the square root of 65

Formula: a^2= c*2-b^2

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5 0
2 years ago
Find the indicated real nth root(s) of a. n=3, a=729
marissa [1.9K]

Answer:

9

Step-by-step explanation:

n=3, a=729

For any odd integer, n ; a will have only one real nth root which will be a positive integer.

Similarly, for any integer, n, that is > 1 ; related by the expression ;

p^n = a ; the nth root of a = p

Therefore,

If n = 3 ; a = 729

p^3 = 729

To obtain the value of p ; take the cube of both sides

(p^3)*1/3 = 729^1/3

p = 9

Hence, the real nth root of 729 is +9 when n = 3

6 0
2 years ago
Please help me please will give brainliest ​
alisha [4.7K]

Answer:

16\sqrt{17}

Step-by-step explanation:

The perimeter is two times width plus two times length:

2\sqrt{17} + 2\cdot 7\sqrt{17} = 2\sqrt{17} + 14\sqrt{17} = 16\sqrt{17}

There is no way to simplify further.

3 0
3 years ago
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