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Eduardwww [97]
3 years ago
15

A box is pushed 40 m by a mover. The amount of work done was 2,240 j. How much force was exerted on the box

Physics
1 answer:
Georgia [21]3 years ago
3 0

The force exerted on the box is 56 N

Explanation:

The work done by a force on an object is given by

W=Fd cos \theta

where

F is the magnitude of the force

d is the displacement of the object

\theta is the angle between the direction of the force and of the displacement

For the box in this problem, we have:

W = 2240 J is the work done

d = 40 m is the displacement of the box

Assuming that the  force is parallel to the displacement, \theta=0

Solving the equation for F, we find the force exerted on the box:

F=\frac{W}{d cos \theta}=\frac{2240}{(40)(cos 0)}=56 N

Learn more about work:

brainly.com/question/6763771

brainly.com/question/6443626

#LearnwithBrainly

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Two football players with mass 75kg and 100kg run directly toward each other with speeds of 6 m/s and 8 m/s respectively, If the
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Answer:

2 m/s

Explanation:

From the law of conservation of momentum,

Total momentum before collision = total momentum after collision

mu+m'u' = V(m+m') .................................Equation 1

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Making V the subject of the equation,

V = (mu+m'u')/(m+m')................ Equation 2

Note: Taking the direction of the first player as positive.

Given: m = 75 kg, m' = 100 kg, u = 6 m/s, u' = -8 m/s (opposite the first player),

Substituting into equation 2

V = [(75×6)+(100×(--8))]/(75+100)

V = (450-800)/175

V = 350/175

V = - 2 m/s.

Note: The negative signs tells that the combined speed is in the direction of the second player.

Hence the combined speed of the two players = 2 m/s

8 0
4 years ago
For a certain ideal Carnot engine, the hot reservoir is 35°C higher than the cold reservoir. If this engine is to have an effici
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Answer:

Temperature of the hot reservoir is 1540K

Explanation:

E= 1- \frac{T_{c}}[tex]{T_h}=308+{T_c}\\Efficiency of a carnot engine is given by the aboveTc=temperature of the cold reservoirTh= temperature of the hot reservoirK=273+ 35  (convert  35°C to kelvin)K=308k{T_h}={T_c}+308-----------------------(equation  1)20%=1-{T_c}/{T_h}

0.2=({T_c}+308-{T_c})/{T_c}+308

.2({T_c}+61.6=308

0.2{T_c}=246.4

{T_c}=1232

recall from equation 1

{T_h}=308+1232

{T_h}=1540K

5 0
3 years ago
The metric unit of force is the _____.<br><br> A.newton<br> B.pound<br> C.kilogram<br> D.watt
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Force = mass × acceleration = kg × m/s^2 = Newton

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4 years ago
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A ball whirls around in a vertical circle at the end of a string. The other end of the string is fixed at the center of the circ
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Answer:

T_b=m(g+\frac{v_b^2}{R})

Explanation:

At the bottom the tension would be upwards and the weight downwards, their difference being the centripetal force. Taking the upwards direction as positive we then have:

T_b-mg=F_{cp}=ma_{cp}=m\frac{v_b^2}{R}

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T_b=m(g+\frac{v_b^2}{R})

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