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riadik2000 [5.3K]
3 years ago
9

A battery with an emf of 24.0 V is connected to a resistive load. If the terminal voltage of the battery is 16.1 V and the curre

nt through the load is 3.90 A, what is the internal resistance of the battery?
Physics
1 answer:
lions [1.4K]3 years ago
6 0

Answer:

2.03 Ω

Explanation:

EMF: This can be defined as the potential difference of a cell when it is not delivering any current. The S.I unit of Emf is Volt.

The formula of emf is given as,

E = I(R+r)............................ Equation 1

Where E = Emf, I = current, R = External resistance, r = internal resistance.

Make r the subject of the equation

r = (E-IR)/I........................ Equation 2

Note: From ohm's law, V = IR.

r = (E-V)/I........................ Equation 3

Where V = Terminal voltage

Given: E = 24 V, I = 3.9 A, V = 16.1 V.

Substitute into equation 3

r = (24-16.1)/3.9

r = 7.9/3.9

r = 2.03 Ω

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<em>Explanation below</em>

Explanation:

<u>Speed vs Velocity </u>

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To compute \vec r, we only need to know the initial and final positions and subtract them. To compute d, we need to add all the distances traveled by the object, regardless of their directions.

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\vec r=1500\ m \text{ to the south}

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\displaystyle \vec v=\frac{1500}{45}=33.33\ m/s\text{ to the south}

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C

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C. 12.8km

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