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exis [7]
3 years ago
15

Two straight wires are in parallel and carry electrical currents in opposite directions with the same magnitude of LaTeX: 2.02.0

LaTeX: AA. The distance between the two wires LaTeX: 5.05.0 LaTeX: mmm m. If one of the wires is infinitely long and the other the wire is LaTeX: 0.30.3 LaTeX: mm long, what is the magnitude of the force between the two wires?
Physics
1 answer:
koban [17]3 years ago
3 0

Answer:

2.4\times 10^{-5} N

Explanation:

We are given that

I_1=I_2=2.0 A

Distance between the wires,d=5.0 mm=5\times 10^{-3} m

1mm=10^{-3} m

Length of other wire,l=0.3 m

Length of one wire is infinite.

We have to find the magnitude of force between the two wires.

We know that magnetic force

F=\frac{2\mu_0 I_1I_2 l}{4\pi d}

Where \frac{\mu_0}{4\pi}=10^{-7}

F=\frac{2\times 10^{-7}\times 2\times 2\times 0.3}{5\times 10^{-3}}

F=2.4\times 10^{-5} N

When the wires carrying equal current in opposite direction then the force between two wires repel to each other.

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An electrical power plant manages to send 88% of the heat produced in the burning of fossil fuel into the water-to-steam convers
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Answer:

A

Explanation:

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Which fossil fuel is produced as a by-product that occurs when bacteria decompose organic material under anaerobic conditions?
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5 0
3 years ago
The charges of two particles are as follows: Q1=2 x 10 -8 C and Q2 = 3 x 10 -7 C. Find the magnitude of the force between these
Fantom [35]

Answer:

F = 3.86 x 10⁻⁶ N

Explanation:

First, we will find the distance between the two particles:

r = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2+(z_{2}-z_{1})^2}\\

where,

r = distance between the particles = ?

(x₁, y₁, z₁) = (2, 5, 1)

(x₂, y₂, z₂) = (3, 2, 3)

Therefore,

r = \sqrt{(3-2)^2+(2-5)^2+(3-1)^2}\\r = 3.741\ m\\

Now, we will calculate the magnitude of the force between the charges by using Coulomb's Law:

F = \frac{kq_{1}q_{2}}{r^2}\\

where,

F = magnitude of force = ?

k = Coulomb's Constant = 9 x 10⁹ Nm²/C²

q₁ = magnitude of first charge = 2 x 10⁻⁸ C

q₂ = magnitude of second charge = 3 x 10⁻⁷ C

r = distance between the charges = 3.741 m

Therefore,

F = \frac{(9\ x\ 10^9\ Nm^2/C^2)(2\ x\ 10^{-8}\ C)(3\ x\ 10^{-7}\ C)}{(3.741\ m)^2}\\

<u>F = 3.86 x 10⁻⁶ N</u>

5 0
3 years ago
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