Answer:
(p ∧ q)’ ≡ p’ ∨ q’
Step-by-step explanation:
First, p and q have just four (4) possibilities, p∧q is true (t) when p and q are both t.
p ∧ q
t t t
t f f
f f t
f f f
next step is getting the opposite
(p∧q)'
<em>f</em>
<em> t</em>
<em> t</em>
<em> t</em>
Then we get p' V q', V is true (t) when the first or the second is true.
p' V q'
f <em>f</em> f
f <em>t</em> t
t <em>t</em> f
t <em>t</em> t
Let's compare them, ≡ is true if the first is equal to the second one.
(p∧q)' ≡ (p' V q')
<em>f f </em>
<em> t t</em>
<em> t t</em>
<em> t t</em>
Both are true, so
(p ∧ q)’ ≡ p’ ∨ q’
Ron should receive $7.98. Jerry and Steve each worked for 4 hours, while Ron was one hour late, so he worked for 3 hours. Together, they worked for 4*2+3=11 hours, receiving $29.25 in total. Each hour should be paid 29.25/11=2.66 dollars. Ron worked for three hours, so he should receive 3*2.66=7.98 dollars.
Answer:
No, its not equivalent
1/2 is equivalent though
Please mark as brainliest
Answer:
so look
Step-by-step explanation:
6x=7+8
2 Simplify 7+87+8 to 1515.
6x=156x=15
3 Divide both sides by 66.
x=\frac{15}{6}x=
6
15
4 Simplify \frac{15}{6}
6
15
to \frac{5}{2}
2
5
.
x=\frac{5}{2}x=
2
5
Done
Decimal Form: 2.5
Answer:
The probability that they will both be on time is 12/25.
Step-by-step explanation:
John is late 20% of the time.
So, he is prompt 80% of the time.
Ted is late 40% of the time.
So, he is prompt 60% of the time.
Since, both the events are independent,
p(John be on time ∩ Ted be on time) = p(John be on time) × p(Ted be on time)
× 
= 0.80 × 0.60
= 0.48 or 48%
Hence, the probability that they will both be on time is 12/25.
