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Maurinko [17]
3 years ago
11

Sarah makes 5 ribbons the first day. On the second day she doubles the number of

Mathematics
2 answers:
sdas [7]3 years ago
7 0
20 ribbons

Explanation:
1st day— 5 ribbons
2nd day—2 x 5 = 10 ribbbns
3rd day— 2 x 10 = 20

Hope this helps
Anna11 [10]3 years ago
4 0

I believe your answer is 20

Step-by-step explanation: When you double 5, you get 10, which would be the amout of ribbons she made on the second day, if you double 10, you get 20.

I hope this helps!

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4/16
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Divide 3 by 4, then subtract z from the result
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Answer:

3/4 = z

Step-by-step explanation:

<u>Step 1:  Convert words into an expression</u>

Divide 3 by 4, then subtract z from the result

3/4 - z

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Find all solutions of the given system of equations (If the system is infinite many solution, express your answer in terms of x)
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Answer:

(a) The system of the equations \left \{ {2x-3y\:=3} \atop {4x-6y\:=3}} \right. has no solution.

(b) The system of the equations \left \{ {4x-6y\:=10} \atop {16x-24y\:=40}} \right. has many solutions y=\frac{2x}{3}-\frac{5}{3}

Step-by-step explanation:

(a) To find the solutions of the following system of equations \left \{ {2x-3y\:=3} \atop {4x-6y\:=3}} \right. you must:

Multiply 2x-3y=3 by 2:

\begin{bmatrix}4x-6y=6\\ 4x-6y=3\end{bmatrix}

Subtract the equations

4x-6y=3\\-\\4x-6y=6\\------\\0=-3

0 = -3 is false, therefore the system of the equations has no solution.

(b) To find the solutions of the system \left \{ {4x-6y\:=10} \atop {16x-24y\:=40}} \right. you must:

Isolate x for 4x-6y=10

x=\frac{5+3y}{2}

Substitute x=\frac{5+3y}{2} into the second equation

16\cdot \frac{5+3y}{2}-24y=40\\8\left(3y+5\right)-24y=40\\24y+40-24y=40\\40=40

The system has many solutions.

Isolate y for 4x-6y=10

y=\frac{2x}{3}-\frac{5}{3}

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