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3 years ago

The fastest a human has ever run is 27 miles per hour. How many miles per minute did the human run?

2 answers:

6 0

$27\ \frac{miles}{hour}\\\\
hour=60minutes\\\\
27*\frac{1miles}{60}=0.45\frac{miles}{minute}\\\\ Human\ run\ 0.45\frac{miles}{minute}.$

nekit [7.7K]3 years ago

3 0

$\frac{27mi}{1hr} * \frac{1hr}{60min}= \frac{27mi}{60min}$

27mi/60min=9/20
9mi/20min=xmi/1min
Cross multiply
Divide by 20 on both sides
x= 9/20

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Write10:15 pm in 24 hour time

Stels [109]

Your answer is 22:15

5 0

3 years ago

How do I solve this question?

Sati [7]

Answer:

m=2 and n=3

Step-by-step explanation:

Step :-

Given $[ 2 x^{n}y^{2} ]^m = 4 x^6 y^4$

using algebraic formula $(a^m)^n= a^{mn}$

now

$2^{m} x^{mn} y^{2m} = 4x^{6} y^{4}$

now equating 'x' powers, we get

$x^{mn} = x^{6}$

$mn=6$ ....(1)

now

$y^{2m} = y^{4}$

Equating 'y' powers ,we get

2 m=4

m=2

substitute m= 2 in equation (1)

we get

2 n=6

n=3

verification:-

substitute m=2 and n=3 , we get

$[ 2 x^{n}y^{2} ]^m = 4 x^6 y^4$

$(2 x^{3} y^2)^2 = 4 x^6 y ^4\\$

$4 x^6 y^4 = 4 x^6 y^4$

both are equating so m= 2 and n=3

4 0

3 years ago

En un grupo de 100 personas 2/5 prefieren sopa de pollo, 4/10 prefieren comer hornado, y el resto prefiere fritada. A) ¿Qué part

castortr0y [4]

In a group of 100 people, 2/5 prefer chicken soup, 4/10 prefer to eat hornado, and the rest prefer frying. What part of the group prefers frying ? How many people prefer each type of food ? (thank u google translate)...I guess

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4/10 out of 100 prefer hornado (I dont even know what that is)...
4/10 * 100 = 400/10 = 40 prefer hornado.

and the rest prefer frying....100 - (40 + 40) = 100 - 80 = 20 (or 1/5) prefer frying

3 0

3 years ago

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Pie

Answer:

$(A\cap B)\cap U$