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Alisiya [41]
2 years ago
12

Determine if the lines are parallel, perpendicular, neither or the same line: y = -2x + 1 and -2x + 4y = 5.

Mathematics
2 answers:
Kazeer [188]2 years ago
8 0

Answer:

sd

Step-by-step explanation:

sd

igomit [66]2 years ago
5 0

Answer:

Determine if the lines are parallel, perpendicular, neither or the same line: y = -2x + 1 and -2x + 4y = 5. Do it ur self

Step-by-step explanation:

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What is the slope of the line through (-9, 6) and (-3, 9)?<br> Choose 1 answer:
trasher [3.6K]

Given: Points (-9, 6) and (-3, 9)

Find:  The slope of the line that goes through those two points

Solution: In order to find the slope of the line that goes through the points that were provided we have to use the slope formula.  This formula subtracts the y-coordinates from each other and also the x-coordinates from each other to determine the rise/run which would give us the rate of change.

<u>Plug in the values</u>

  • m = \frac{y_2 - y_1}{x_2 - x_1}
  • m = \frac{9 - 6}{-3 - (-9)}

<u>Simplify the expression</u>

  • m = \frac{3}{-3 + 9}
  • m = \frac{3}{6}
  • m = \frac{1}{2}

Therefore, looking at the given options we can see that the best fitting one would be option A, 1/2.

4 0
1 year ago
Read 2 more answers
I NEED HELP!! please show all work
PtichkaEL [24]

Take the logarithm of both sides. The base of the logarithm doesn't matter.

4^{5x} = 3^{x-2}

\implies \log 4^{5x} = \log 3^{x-2}

Drop the exponents:

\implies 5x \log 4 = (x-2) \log 3

Expand the right side:

\implies 5x \log 4 = x \log 3 - 2 \log 3

Move the terms containing <em>x</em> to the left side and factor out <em>x</em> :

\implies 5x \log 4 - x \log 3 = - 2 \log 3

\implies x (5 \log 4 - \log 3) = - 2 \log 3

Solve for <em>x</em> by dividing boths ides by 5 log(4) - log(3) :

\implies \boxed{x = -\dfrac{ 2 \log 3 }{ 5 \log 4 - \log 3 }}

You can stop there, or continue simplifying the solution by using properties of logarithms:

\implies x = -\dfrac{ \log 3^2 }{ \log 4^5 - \log 3 }

\implies x = -\dfrac{ \log 9 }{ \log 1024 - \log 3 }

\implies \boxed{x = -\dfrac{ \log 9 }{ \log \frac{1024}3 }}

You can condense the solution further using the change-of-base identity,

\implies \boxed{x = -\log_{\frac{1024}3}9}

5 0
2 years ago
Need help solving for X
Inessa05 [86]
You can find the complementary angle for 28° first, which is 90°-28°=62°. Since this is a right triangle, you can then use trigonometry to find x (the hypotenuse). You have the angle and the adjacent side, so plug and play:

cos 62° = 350 / x
x = 350 / cos 62°
x = 745.5 ft
8 0
3 years ago
Read 2 more answers
What do you think is true of a line and a point not on the line? Explain
statuscvo [17]
The point is not a solution to the equation of the line.

Hope this helps!
3 0
3 years ago
What is the solution for -10 &lt; x - 9?
enyata [817]
<span>-10 < x - 9

</span><span>-10+9 < x - 9+9

-1<x, or
x> - 1</span>
4 0
3 years ago
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