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4 years ago

An atom of chromium has 24 protons, 28 neutrons, and 24 electrons. A chromium atom has_____Subatomic particles in the necleus

Chemistry

1 answer:

navik [9.2K]4 years ago

5 0

3 subatomic particles in the nucleus
which is proton(24),neutron (28) and electrons(24)

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2. Aim: I don't know, i don

Sonja [21]

I dunnnooooooo dunnooooo

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2 years ago

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True or false energy has no mass and takes up no space

ivanzaharov [21]

Answer:

False

Explanation:

Energy takes up space as mass is a form of energy and energy is always constant.

4 0

3 years ago

Calculate E o , E, and ΔG for the following cell reactions (a) Mg(s) + Sn2+(aq) ⇌ Mg2+(aq) + Sn(s) where [Mg2+] = 0.025 M and [S

Rudik [331]

E⁰(cell) = 2.24V

E(cell) = 2.246V

∆G = -433 KJ/mol

<u>Explanation:</u>

Mg(s) + Sn²⁺(aq) ⇌ Mg²⁺(aq) + Sn(s)

[Mg2+] = 0.025 M

[Sn2+] = 0.040 M

First we need the standard reduction potentials:

. . . . . . . . . . . . . . . . . E°(V)

Mg²⁺ + 2 e⁻ ⇌ Mg(s). . .−2.372

Sn²⁺ + 2 e⁻ ⇌ Sn(s) . . . −0.13

Take the more negative (or less positive in other cases) one, and write it as an oxidation:

Mg(s) ⇌ Mg²⁺ + 2 e⁻. . .+2.372 V

Combine them,

Mg(s) + Sn²⁺ ⇌ Mg²⁺ + Sn(s)

E°(cell) = +2.372 – 0.13 V = 2.24 V

To get the cell potential under the conditions given, use the Nernst Equation:

E(cell) = E°(cell) – [(0.059)/n]•logQ = 2.24 V – 0.0295 V • log [Mg²⁺]/[Sn²⁺]

Note that the solids don't appear in Q, only the concs. of the dissolved ions.

E(cell) = 2.24 V – 0.0295 V X log (0.025)/(0.040)

= 2.24 + 0.006 V ≈ 2.246 V

The concentration ratio in Q (Sn²⁺ and Mg²⁺) is too close to 1 to shift E(cell) significantly from E°(cell) given the precision I have for the Sn reduction potential.

∆G = –nFE(cell) = –2(96.485 kJ/mol•V)(2.246 V) = –433 kJ/mol

E⁰(cell) = 2.24V

E(cell) = 2.246V

∆G = -433 KJ/mol

4 0

4 years ago

The (15-35-15) number on a bag of fertilizer is calculated by an outdated method. All modern fertilizers use PO43- as a source o

Alik [6]

The (15-35-15) number on a bag of fertilizer is calculated by an outdated method. Using the knowledge of the old methods, the number of moles of phosphorus found in 10.0 grams of phosphorus is 0.05 mole.

The (15-35-15) number on the bag of fertilizer is used for:

Nitrogen 15 : Phosphorus pentoxide 35: potassium oxide 15

Thus, in a 100-gram bag of fertilizer, there are 35 grams of phosphorus pentoxide P₂O₅.

∴

To determine the number of moles of 10 grams of phosphorus pentoxide in (15-35-15) bag of fertilizer, we have:

$\mathbf{=10 \times \dfrac{35}{100} \ grams \ of \ P_2O_5}$

= 3.5 grams of P₂O₅

Recall that:

$\mathbf{Number of moles = \dfrac{mass}{molar \ mass}}$

the molar mass of P₂O₅ = 142 g/mol

∴

$\mathbf{Number of moles = \dfrac{3.5\ g}{ 142 \ g/mol}}$

$\mathbf{Number of moles = 0.0246 \ mol}$

Provided that 1 mole of P₂O₅ harbors 2 moles of phosphorus;

Then;

The number of phosphorus present in 10.0 grams of (15-35-15) fertilizer is:

= 0.0246 moles × 2

= 0.0492 moles

≅ 0.05 moles

Therefore, we can conclude that the number of moles of phosphorus found in 10.0 grams of (15-35-15) bag of fertilizer is 0.05 moles.

Learn more about phosphorus here:

brainly.com/question/4622631?referrer=searchResults

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2 years ago

What are the main risk and main benefit when a society uses energy from nuclear fission?

BlackZzzverrR [31]

Answer:

Explanation:

Nuclear energy does not have greenhouse gas emissions. The emissions produced by nuclear fission plants are similar to renewable energy sources.The generation of power using nuclear energy does not affect air quality thus providing a clean source of energy.Nuclear energy originates from radioactive material which are harmful to living organisms.

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3 years ago

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