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PSYCHO15rus [73]
4 years ago
9

An atom of chromium has 24 protons, 28 neutrons, and 24 electrons. A chromium atom has_____Subatomic particles in the necleus

Chemistry
1 answer:
navik [9.2K]4 years ago
5 0
3 subatomic particles in the nucleus
which is proton(24),neutron (28) and electrons(24)
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Substances that have a define size and shape and vibrating particles that are close together are​
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Substances that have a define size and shape and vibrating particles that are close together are called Solid.

Explanation:

There are three states of matter - solid, liquid and gas.

Lets talk about solid state in detail.

In solid particles are closely packed and so they have very less or no space to move which results in vibrating particles. This results in solid substances having a fixed shape and volume.

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3 years ago
The oxidation of Cu₂O(s) to CuO(s) is an exothermic process:
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Answer:

w = 7376.6 J

Explanation:

To calculate the work done in the system, we need first to calculate the number of moles of all compounds.

The following expression, that comes from the 1° law of thermodynamic, will help you to get the work:

w = ΔnRT

Where:

Δn: difference in the number of moles between products and reactants

R: constant universal of gases (8.314 J / mol K)

T: Temperature in Kelvin.

As we are doing this reaction in STP, then the Pressure is 1 atm, and temperature is 0 °C or 273 K.

Now, we already have the moles of Cu₂O, let's see, according to the balanced reaction, how many moles we should have of O₂ and CuO.

If 1 mole of O₂ reacts with 2 moles of Cu₂O then 6.5 moles of Cu₂O will be:

moles O₂ = 6.5 moles Cu₂O * (1 mole O₂/2 moles Cu₂O) = 3.25 moles O₂

If 2 moles of Cu₂O produces 4 moles of CuO, then 6.5 moles will be:

moles CuO = 6.5 moles Cu₂O*(4 moles CuO/2 moles Cu₂O) = 13 moles CuO

Now that we have the moles, let's calculate the value of Δn.

Δn = moles product - moles reactants

Δn = 13 - (6.5 + 3.25) = 3.25 moles

Now, we can calculate the work done in the system:

w = 3.25 * (8.314 * 273)

<h2>w = 7376.6 J or 7.3766 kJ</h2>

Hope this helps

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