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maw [93]
2 years ago
14

True or false, rewrite it to make it true.

Chemistry
1 answer:
Orlov [11]2 years ago
8 0

Answer:

false

Explanation:

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How many molecules are present in the following quantity<br> 0.250 mole of H2O
klio [65]
If  1mole ------------- is ---------------- 6.02*10²³
than 0.25mole ----- is ----------------  x

x = [0.25mole*6.02*10²³]/1mole = <u>1,505*10²³</u>
4 0
3 years ago
At a certain temperature the vapor pressure of pure chloroform (CHCl3) is measured to be 91. torr. Suppose a solution is prepare
OleMash [197]

Answer:

P_{CCl_4}=52.43torr

Explanation:

Hello there!

In this case, sine the solution of this problem require the application of the Raoult's law, assuming heptane is a nonvolatile solute, so we can write:

P_{CCl_4}=x_{CCl_4}P_{CCl_4}^{vap}

Thus, we first calculate the mole fraction of chloroform, by using the given masses and molar masses as shown below:

x_{CCl_4}=\frac{140/153.81}{140/153.81+67.1/100.21}=0.576

Therefore, the partial pressure of chloroform turns out to be:

P_{CCl_4}=0.576*91torr\\\\P_{CCl_4}=52.43torr

Regards!

3 0
3 years ago
An archer pulls her bowstring back 0.370 m by exerting a force that increases uniformly from zero to 264 N. (a) What is the equi
Arte-miy333 [17]

Answer:

713.51 N/m

Explanation:

Hook's Law: This law states that provided the elastic limit is not exceeded, the extension in an elastic material is directly proportional to the applied force.

From hook's law,

F = ke ...........................Equation 1

Where F = Force exerted on the bowstring, e = Extension/compression of the bowstring, k = Spring constant of the bow.

Make k the subject of the equation,

k = F/e ............................ Equation 2

Given: F = 264 N, e = 0.37 m.

Substitute into equation 2

k = 264/0.37

k = 713.51 N/m

Hence the spring constant of the bow  = 713.51 N/m

3 0
3 years ago
each year, one person in north america uses resources equal to how much land? A. 12 miles B. 12 acres C. 120 acres
KATRIN_1 [288]
B. 12 acres

i think i don’t do geography
4 0
3 years ago
The boiling point of another member of this homologous series was found to be 309 k. What is the likely molecular formula for th
Sati [7]

Answer:

C5H12

Explanation:

In organic chemistry the boiling point of 309 k is of fifth member of alkane series which Pentane whose molecular mass is 72 g/mol.  Thus, we can say that the  molecular formula of the compound which has boiling point 309 K is C5H12.

3 0
3 years ago
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