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Advocard [28]
3 years ago
5

A large community college has professors and lecturers the total number of faculty members is 136.The school reported that they

had six professors for every 11 lecturers how many professors does the Community College employ
Mathematics
1 answer:
Alona [7]3 years ago
4 0

Answer:

  48

Step-by-step explanation:

The ratio of professors to lecturers is ...

  P : L = 6 : 11

Then the ratio of professors to total faculty is ...

  P : (P+L) = 6 : (6+11) = 6 : 17

That is, professors make up 6/17 of the total faculty. Their number is ...

  P = (6/17)·136 = 48

The Community College employs 48 professors.

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The Odd and even numbered hotel rooms are on different sides of the hall room 23q is between which two rooms
diamong [38]
It is between room 21 and 25
6 0
3 years ago
Help me Please....................
MakcuM [25]

9514 1404 393

Answer:

  1.3363

Step-by-step explanation:

The basic idea here is to find an expression for the direction vector between a point on L1 and a point on L2. Then, solve for the points on L1 and L2 that make that vector perpendicular to both lines L1 and L2. (The dot product of direction vectors is zero.) The distance between the points found is the shortest distance between the lines.

__

Let P be a point on L1. Then the parametric equation for P is ...

  P = (6t, 0, -t) . . . . . . origin + t × direction vector

Let Q be a point on L2. The direction vector for L2 is given by the difference between the given points. It is (4-1, 1-(-1), 6-1) = (3, 2, 5). Then the parametric equation for Q is ...

  Q = (3s+1, 2s-1, 5s+1) . . . . (1, -1, 1) + s × direction vector

The direction vector for PQ is ...

  Q -P = (3s+1-6t, 2s-1, 5s+1+t)

The dot product of this and the two lines' direction vectors will be zero:

  (3s+1-6t, 2s-1, 5s+1+t)·(6, 0, -1) = 0 = 13s -37t +5 . . . perpendicular to L1

  (3s+1-6t, 2s-1, 5s+1+t)·(3, 2, 5) = 0 = 38s -13t +6 . . . perpendicular to L2

The solution to these equations is ...

  s = -157/1237

  t = 112/1237

Then (Q-P) becomes (94, -1551, 564)/1237, and its length is ...

  |PQ| = √(94² +1551² +564²)/1237 ≈ 1.3363

The distance between the two lines is about 1.3363 units.

8 0
3 years ago
. 4/18 times 2/92. 1/9 times 3/63. 12/14 times 1/84.1/7 times 5/65. 17/20 times 1/61. 4 1/4 times 3 1/22. 3 5/6 times 4 1/23. 2
AlladinOne [14]

Answer:

Step-by-step explanation:

4/18×2/92

=1/9×1/23

=1/207

1/9×3/63

=1/3×1/23

=1/69

12/14×1/84

=1/14×1/7

=1/98

1/7×5/65

=1/7×1/13

=1/91

17/20×1/61

=17/1220

4 1/4 ×3 1/22

=17/4×67/22

=1,139/88

=12 83/88

3 5/6×4 1/23

=23/6×93/23

=93/6

=15 3/6

=15 1/2

2 1/2×4 7/84

=5/2×343/84

=1715/168

=10 35/168

I have answered more than 2 from each set

6 0
3 years ago
Simplify 3 to the power of 1
lina2011 [118]

3 to the power of 1 simplified, is just 3.

7 0
3 years ago
Read 2 more answers
After 200 feet of drilling on the first well, a soil test is taken. The probabilities of finding the particular type of soil ide
dimaraw [331]

Answer:

The revised probabilities are;

The probability of finding soil with oil  = 0.8  

The probability of finding soil with good oil = 0.16

The probability of finding medium quality oil =  0.64

Step-by-step explanation:

The given probability of finding soil with high quality oil, P(QO) = 0.20

The probability of finding soil with medium-quality oil, P(OM) = 0.80

The probability of finding soil with no oil, P(ON) = 0.2

Therefore, given that the probability of finding soil with no oil = 0.2, we have;

The probability of finding soil with oil, P(OP) = 1 - the probability of finding soil with no oil

P(OP) = 1 - 0.2 = 0.8

Which gives;

The probability, P(FG) of finding soil with oil and that the oil is good is given as follows;

P(FG) = P(QO) × P(OP) = 0.2 × 0.8 = 0.16

The probability of finding good oil = 0.16

Similarly;

The probability of finding medium quality oil P(FM) =  P(OM) × P(OP) = 0.8 × 0.8 = 0.64

Which gives the revised probability as follows;

The probability of finding soil with oil, P(OP) = 0.8  

The probability of finding soil with good oil, P(FG) = 0.16

The probability of finding medium quality oil, P(FM) =  0.64.                

3 0
3 years ago
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