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fomenos
3 years ago
13

A ray of yellow light has a wavelength of about 5.8×10−7 m. Will exposure to yellow light cause electrons to be emitted from ces

ium?
Chemistry
1 answer:
Igoryamba3 years ago
7 0
The threshold frequency of Cesium is 5.2 x 10^14 Hz.

To find the frequency of yellow light, we use the equation:
speed of light = wavelength x frequency
3 x 10^8 = 5.8 x 10^-17 x frequency
frequency = 5.17 x 10^24

This is higher than the threshold frequency of Cesium, thus, electrons will be emitted.

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nswer the following questions relating to HCl, CH3Cl, and CH3Br.HCl(g), can be prepared by the reaction of concentrated H2SO4(ag
alexdok [17]

Answer:

It is an example of double displacement reaction.

4.8 g of NaCl is needed to react.

Explanation:

Balanced reaction: H_{2}SO_{4}(aq.)+2NaCl(s)\rightarrow 2HCl(g)+Na_{2}SO_{4}(aq.)

Here, oxidation states of H, S, O, Na and Cl do not change during reaction. Hence it is not a redox reaction.

In this reaction, cations and anions of the reactants interchange their partners during reaction. Hence, it is an example of double displacement reaction.

As H_{2}SO_{4}(aq.) remain in excess amount therefore NaCl (s) is the limiting reagent. Hence production of HCl entirely depends on amount of NaCl used.

Molar mass of HCl = 36.46 g/mol

So, 3.0 g of HCl = \frac{3.0}{36.46} mol of HCl = 0.082 mol of HCl

According to balanced equation-

2 moles of HCl are produced from 2 moles of NaCl

So, 0.082 moles of HCl are produced from 0.082 moles of NaCl

Molar mass of NaCl = 58.44 g/mol

So, mass of 0.082 moles of NaCl = (0.082\times 58.44) g = 4.8 g

Hence 4.8 g of NaCl is needed to react.

4 0
3 years ago
Helppppppppppp please
valentinak56 [21]
Your answer would have to be #3
4 0
3 years ago
What is the mass of an atom that has 10 protons, 13 neutrons, and 10 electrons? 10 20 23 33?
zlopas [31]
It would be 23, s choice C. 
3 0
3 years ago
Which group has eight valence electrons?
sesenic [268]

Answer:

alkali metals is your answer

3 0
2 years ago
Mr. Holmes and Mrs. Nogaki are having a good old fashioned Baby Back Ribs BBQ contest and are arguing over who’s BBQ produces le
ExtremeBDS [4]

Answer:

Mrs. Nogaki is right because Mr. Holmes’s BBQ produces 3x more CO2 for each mole of fuel burned.

Explanation:

Now Mrs. Nogaki has already figured out the chemical combustion reaction behind the operation of her BBQ. It is pertinent to reproduce it here.

CH4(g) + 2O2(g)→CO2(g) +2H2O(g)

She already has this figured out but Mr. Holmes doesn't have any chemical reaction equation to back his claims. Let us help him with the correct combustion equation for propane.

C3H8(g) + 5O2(g) + 3CO2(g) + 4H2O(g)

We can clearly see from the reaction equation that Mr. Holmes BBQ produces three times more carbon IV oxide than Mr. Nogaki's BBQ so Mr. Nogaki was right in her claim after all.

Hence the answer!

5 0
3 years ago
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