Answer:
Explanation:
The model written correctly is:
This is a mathematical question, instead of a chemistry question, and you should use calculus to find the nitrogen level that gives the best yield, since this is an optimization problem.
The best yield is the maximum yield, and the maximum, provided that it exists, is found using the first derivative and making it equal to zero: Y' = 0
To find Y' you must use the quotient rule.

Now make Y' = 0
- The denominator is never equal to zero, because it is always positive and greater than 9.
- Make the numerator equal to zero:
9k - kN² = 0
- Since k is a positve constant, it is not equal to zero, and the other factor, 9 - N², must be equal to zero:
9 - N² = 0 ⇒ (3 - N) (3 + N) = 0
⇒ 3 - N = 0 or 3 + N = 0 ⇒ N = 3 or N = -3.
Since N is nitrogen level, it cannot be negative and the only valid answer is N = 3.
You can prove that it is a maximum (instead of a minimum) finding the second derivative or testing some points around 3 (e.g. 2.5 and 3.5).
Answer:
Chemical properties can be recognized only when substances react or do not react chemically with one another, that is, when they undergo a change in composition. A chemical property of one substance usually involves its ability to react or not react with another specific substance.
Answer:
For your first question, Curium does not occur naturally on Earth, meaning that it is not produced naturally on Earth. However, it can be formed in nuclear reactors.
For your second question, Curium has been used to provide power to electrical equipment used on space missions, but doesn't seem to be that important overall.
Explanation:
Hope this helped!
Answer:Option (3) less than the sum of its components' masses
Explanation:
Explanation:
substance Q could be <em><u>oxygen (O2)</u></em>
substance R could be <em><u>carbon</u></em><em><u> </u></em><em><u>d</u></em><em><u>i</u></em><em><u>o</u></em><em><u>x</u></em><em><u>i</u></em><em><u>d</u></em><em><u>e</u></em><em><u> </u></em><em><u>(</u></em><em><u>C</u></em><em><u>O</u></em><em><u>2</u></em><em><u>)</u></em>