The answer i B just finished this.
1 out 12 is the probability of it being raspberry-filled.
Company A : C = 35D + 15....C is total cost and D is number of days
company B : C = 42D + 10...C is total cost and D is number of days
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which company charges less for renting for 6 days
company A :
C = 35(6) + 15 = 225
company B :
C = 42(6) + 10 = 262
so company A charges less when renting for 6 days
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for 10 days...
company A :
C = 35(10) + 15 = 365
company B :
C = 42(10) + 10 = 430
so there would be (430 - 365) = 65 saved when using company A instead of company B
For a known standard deviation, the confidence interval for sample size = n is
where
x = average
n = sample size
= stad. deviation
z = contant that reflects confidence interval
Let a = x
Let b =
From the given information,
a - b = 0.432 (1)
a + b = 0.52 (2)
Add (1) and (2): 2a = 0.952 => a = 0.476
Subtract (2) from (1): -2b = -0.088 => b = 0.044
Therefore, the confidence interval may be written as
(0.476 - 0.044, 0.476 + 0.044), or as
(0.476
0.044)
Answer:
Rs 42000 and Rs 40000
Step-by-step explanation:
Given that Rs 82000 is divided into two parts.
Let the first part be Rs x which is compounded annually at the interest of 5% per annum for 2 years.
The rate of interest = 5%=0.05
The total amount after 2 years
The other part is Rs 82000-x which is compounded annually at the interest of 5% per annum for 3 years.
The total amount after 3 years
As both the amounts are equal, so from equation (i) and (ii)
x= 42000
And the other part = 82000-42000 = Rs 40000
Hence, he divides the money as
Rs 42000 at 5% per annum compound interest in 2 years and
Rs 40000 at 5% per annum compound interest in 3 years.