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3 years ago

Find two integers whose sum -7 and whose product is 12

2 answers:

7 0

So we factor 12
remember that (-) times (-)=(+)
and
(-)+(-)=(-) so therefor the factors must be negative
factor 12
2,2,3

we have
-2 times -6 which adds to -8
-3 times -4 wihch adds to -7

the numbers are -3 and -4

iren2701 [21]3 years ago

5 0

The two integers are -3 and -4. -3 + -4 is -7. And multiplied together, it is 12.

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3 years ago

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The first term of an arithmetic sequence is-3 and the 15 term is 53. What is the common difference of the sequence?

Annette [7]

$a_2=a_1+d$
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3 years ago

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3 years ago

1/5 (4-3x) = 1/7 (3x - 4) pls solve

natulia [17]

$\huge \boxed{\mathfrak{Question} \downarrow}$

$\large\sf\frac{1}{5} (4 - 3x) = \frac{1}{7} (3x - 4) \\$

$\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}$

$\frac{1}{5} (4 - 3x) = \frac{1}{7} (3x - 4) \\$

Use the distributive property to multiply 1/5 by 4-3x.

$\frac{1}{5}\times 4+\frac{1}{5}\left(-3\right)x=\frac{1}{7}\left(3x-4\right) \\$

Multiply 1/5 and 4 to get 4/5.

$\frac{4}{5}+\frac{1}{5}\left(-3\right)x=\frac{1}{7}\left(3x-4\right) \\$

Multiply 1/5 and -3 to get -3/5.

$\frac{4}{5}+\frac{-3}{5}x=\frac{1}{7}\left(3x-4\right) \\$

Use the distributive property to multiply 1/7 by 3x-4.

$\frac{4}{5}-\frac{3}{5}x=\frac{1}{7}\times 3x+\frac{1}{7}\left(-4\right) \\$

Multiply 1/7 and 3 to get 3/7 & 1/7 × -4 to get -4/7.

$\frac{4}{5}-\frac{3}{5}x=\frac{3}{7}x-\frac{4}{7} \\$

Subtract $\frac{3}{7}x\\$ from both sides.

$\frac{4}{5}-\frac{3}{5}x-\frac{3}{7}x=-\frac{4}{7} \\$

Combine $-\frac{3}{5}x\\$ and $-\frac{3}{7}x\\$ to get $-\frac{36}{35}x\\$ .

$\frac{4}{5}-\frac{36}{35}x=-\frac{4}{7} \\$

Subtract 4/5 from both sides.

$-\frac{36}{35}x=-\frac{4}{7}-\frac{4}{5} \\$

The least common multiple of 7 and 5 is 35. Convert -4/7 and 4/5 to fractions with denominator 35.

$-\frac{36}{35}x=-\frac{20}{35}-\frac{28}{35} \\$

Because $-\frac{20}{35} \\$ and $\frac{28}{35}\\$ have the same denominator, subtract them by subtracting their numerators.

$-\frac{36}{35}x=\frac{-20-28}{35} \\$

Subtract 28 from -20 to get -48.

$-\frac{36}{35}x=-\frac{48}{35} \\$

Multiply both sides by $-\frac{35}{36}\\$ , the reciprocal of $-\frac{36}{35}\\$ .

$x=-\frac{48}{35}\left(-\frac{35}{36}\right) \\$

Multiply $-\frac{48}{35}\\$ by $-\frac{35}{36}\\$ by multiplying the numerator by the numerator and the denominator by the denominator.

$x=\frac{-48\left(-35\right)}{35\times 36} \\$

Carry out the multiplications in the fraction $\frac{-48\left(-35\right)}{35\times 36}\\$ .

$x=\frac{1680}{1260} \\$

Reduce the fraction 1680/1260 to its lowest terms by extracting and cancelling out 420.

$\huge \boxed{ \boxed{ \bf \: x=\frac{4}{3} \approx \: 1.33}}$

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3+(4×12) in expression words

Lena [83]

3 increased by the product of 4 and 12 is 3 + (4 * 12)

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