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irinina [24]
3 years ago
6

Look at the densities of the jovian planets given in figure 1. which of the following statements best describes the pattern of j

ovian planet densities?
Physics
2 answers:
barxatty [35]3 years ago
4 0

more than 5.5 times the density of water

is the answer.

avanturin [10]3 years ago
3 0
Given the densities of the jovian planets, the densities is just like random numbers, so the densities of the jovian planets have no concrete pattern due to its randomness. pattern can be either linear or geometric, where linear you see a common difference among data, while geometric you observed a common ratio
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Use the drop-down menus to complete the sentences.
Grace [21]

Answer:

1) thinner, diverge

2) thicker, converge

Explanation:

i got it right

5 0
3 years ago
Read 2 more answers
Here is a force diagram of an object in water. The weight of the object is 15N and the buoyancy force is 17N. Will the object fl
lawyer [7]

Answer:

Object will float.

Explanation:

Total force on the body = Weight of body + Buoyancy force on body.

 Weight of body = 15 N downwards = 15 N

 Buoyancy force on body = 17 N upwards = -17 N

 Total force on body = 15 - 17 = -2 N = 2 N upwards

 So, the body will float.

Object will float.

8 0
3 years ago
A person must pull a rope 20 meters with a force of 200 N what is the work input?
tatiyna
Work done = force * distance
work done = 200 * 20
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4 0
3 years ago
QUESTION 1
Sveta_85 [38]

distance from the Sun of 2.77 astronomical units or about 414 million km 257 million miles and orbiting period of 4.62 years

7 0
3 years ago
A parallel-plate capacitor has a plate area of 0.2 m^2 and a plate separation of 0.1 mm. If the charge on each plate has a magni
barxatty [35]

Answer:

The potential difference across the plates is 226 V.

Explanation:

Given;

area of the capacitor plate, A = 0.2 m²

separation, d = 0.1 mm = 0.1 x 10⁻³ m

charge on each plate, Q = 4 x 10⁻⁶ C

Charge on the capacitor is given by;

Q = CV

Where;

C is the capacitance of the capacitor, given as;

C = ε₀A / d

Then, the potential difference across the plates is given by;

V = \frac{Q}{C} = \frac{Qd}{\epsilon_o A} = \frac{(4*10^{-6})(0.1*10^{-3})}{(8.85*10^{-12})(0.2)}\\\\V = 226 \ V

Therefore, the potential difference across the plates is 226 V.

5 0
3 years ago
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