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irinina [24]
3 years ago
6

Look at the densities of the jovian planets given in figure 1. which of the following statements best describes the pattern of j

ovian planet densities?
Physics
2 answers:
barxatty [35]3 years ago
4 0

more than 5.5 times the density of water

is the answer.

avanturin [10]3 years ago
3 0
Given the densities of the jovian planets, the densities is just like random numbers, so the densities of the jovian planets have no concrete pattern due to its randomness. pattern can be either linear or geometric, where linear you see a common difference among data, while geometric you observed a common ratio
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8 colors according to their alphabetical order​
damaskus [11]

Answer:

8 colors in alphabetical order are

Black

blue

brown

Green

Orange

Pink

Purple

Yellow

Explanation:

6 0
2 years ago
g stAn experienced spear fisherman sees a small fish swimming in a tidal pool. If the fisherman sees the fish at approximately a
Luba_88 [7]

Answer:

  θ = 28.9

Explanation:

For this exercise let's use the law of refraction

          n₁ sin θ₁ = n₂ sin θ₂

where we use index 1 for air and index 2 for water where the fish is

        sin θ₂ = n₁ / n₂ sin θ₁

in this case the air repair index is 1 and the water 1.33

we substitute

        sin θ₂ = 1 / 1.33 sin t 40

        sin θ = 0.4833

         

        θ = sin⁻¹ 0.4833

        θ = 28.9

5 0
3 years ago
Please help i’ll mark you
suter [353]

Answer:

What should I do. reply quickly for a quick answer

8 0
2 years ago
Read 2 more answers
Which example involves the transformation of chemical energy directly into light energy?
zimovet [89]

burning sodium or magnesium

8 0
3 years ago
Question 1 of 25
finlep [7]

Answer:

<em>2.753*10^-11N</em>

Explanation:

According to Newton's law of gravitation, the force between the masses is expressed as;

F = GMm/d²

M and m are the distances

d is the distance between the masses

Given

M = 3.71 x 10 kg

m = 1.88 x 10^4 kg

d = 1300m

G = 6.67 x 10-11 Nm²/kg

Substitute into the formula

F = 6.67 x 10-11* (3.71 x 10)*(1.88 x 10^4)/1300²

F = 46.52*10^(-6)/1.69 * 10^6

F = 27.53 * 10^{-6-6}

F = 27.53*10^{-12}

F = 2.753*10^-11

<em>Hence the gravitational force between the asteroid is 2.753*10^-11N</em>

<em></em>

6 0
3 years ago
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