A particle of charge 3.53×10 −8 C experiences a force of magnitude 6.03×10 −6 N when it is placed in a particular point

Question

3 years ago

11

in an electric field. What is the magnitude of the electric field at that point?

1 answer:

Cloud [144] · Answer 1 · 2022-03-25T23:28:15+03:00

<h2>Electric field at the location of the charge is 169.97 N/C</h2>

Explanation:

Electric field is the ratio of force and charge.

Force, F = 6 x 10⁻⁶ N

Charge, q = 3.53 x 10⁻⁸ C

We have

$E=\frac{F}{q}\\\\E=\frac{6\times 10^{-6}}{3.53\times 10^{-8}}\\\\E=169.97N/C$

Electric field at the location of the charge is 169.97 N/C

A particle of charge 3.53×10 ​−8 ​​ C experiences a force of magnitude 6.03×10 ​−6 ​​ N when it is placed in a particular point